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An electron of mass m when accelerated through a potential difference V has de Broglie wavelength λ. The de Broglie wavelength associated with a proton of mass M accelerated through the same potential difference will be
  • a)
    λ m/M
  • b)
    λ √m/M
  • c)
    λ M/m
  • d)
    λ √M/m
Correct answer is option 'B'. Can you explain this answer?
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An electron of mass m when accelerated through a potential difference ...
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An electron of mass m when accelerated through a potential difference ...
The de Broglie wavelength of an electron accelerated through a potential difference V can be determined using the following formula:

λ = h / √(2 * m * e * V)

Where:
- λ is the de Broglie wavelength of the electron
- h is the Planck's constant (approximately 6.62607015 × 10^-34 m^2 kg / s)
- m is the mass of the electron
- e is the elementary charge (approximately 1.602176634 × 10^-19 C)
- V is the potential difference

Note that the mass of an electron is approximately 9.10938356 × 10^-31 kg.
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