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The pollution in normal atmosphere is less than 0.01%. Due to leakage of methyl isocyanide (MIC) from a factory the pollution is increased to 20%. If every day 80% of the pollution in the atmosphere is neutralized, in how many days will the atmosphere become normal?
  • a)
    6 days
  • b)
    3 days
  • c)
    4 days
  • d)
    None of these
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The pollution in normal atmosphere is less than 0.01%. Due to leakage ...
The pollution has been increased to 20%.
Every day, 80% pollution is being neutralized, so only 20% of the total pollution remains the next day.
Let x days be needed to bring back the pollution to normal.
Thus, (0.2)x×0.2<0.0001
⇒(0.2)x<0.0005
We have (0.2)4=0.0016 and (0.2)= 0.00032 (can guess the value x on the basis of number of digits after decimal point too)
Hence,minimum of 6 days will be required to bring the pollution back to normal.
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Most Upvoted Answer
The pollution in normal atmosphere is less than 0.01%. Due to leakage ...
To solve this problem, we need to calculate the number of days it will take for the pollution in the atmosphere to decrease from 20% to less than 0.01%.

Let's assume that the total pollution in the atmosphere is 100 units.

1. Calculate the initial pollution caused by the leakage of MIC:
- 20% of 100 units = 20 units

2. Calculate the pollution remaining after neutralization each day:
- 80% of the pollution is neutralized each day, so the remaining pollution is:
- Day 1: 20 units * 0.8 = 16 units
- Day 2: 16 units * 0.8 = 12.8 units
- Day 3: 12.8 units * 0.8 = 10.24 units
- Day 4: 10.24 units * 0.8 = 8.192 units
- Day 5: 8.192 units * 0.8 = 6.5536 units
- Day 6: 6.5536 units * 0.8 = 5.24288 units

3. Continue this process until the pollution is less than 0.01%:
- Day 7: 5.24288 units * 0.8 = 4.194304 units
- Day 8: 4.194304 units * 0.8 = 3.3554432 units
- Day 9: 3.3554432 units * 0.8 = 2.68435456 units
- Day 10: 2.68435456 units * 0.8 = 2.147483648 units
- Day 11: 2.147483648 units * 0.8 = 1.7179869184 units
- Day 12: 1.7179869184 units * 0.8 = 1.3743895347 units
- Day 13: 1.3743895347 units * 0.8 = 1.0995116278 units
- Day 14: 1.0995116278 units * 0.8 = 0.8796093022 units
- Day 15: 0.8796093022 units * 0.8 = 0.7036874418 units

4. After 15 days, the pollution in the atmosphere is less than 0.01%, so it becomes normal.

Therefore, the correct answer is option A) 6 days.
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Community Answer
The pollution in normal atmosphere is less than 0.01%. Due to leakage ...
The pollution has been increased to 20%.
Every day, 80% pollution is being neutralized, so only 20% of the total pollution remains the next day.
Let x days be needed to bring back the pollution to normal.
Thus, (0.2)x×0.2<0.0001
⇒(0.2)x<0.0005
We have (0.2)4=0.0016 and (0.2)= 0.00032 (can guess the value x on the basis of number of digits after decimal point too)
Hence,minimum of 6 days will be required to bring the pollution back to normal.
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Question Description
The pollution in normal atmosphere is less than 0.01%. Due to leakage of methyl isocyanide (MIC) from a factory the pollution is increased to 20%. If every day 80% of the pollution in the atmosphere is neutralized, in how many days will the atmosphere become normal?a)6 daysb)3 daysc)4 daysd)None of theseCorrect answer is option 'A'. Can you explain this answer? for Quant 2025 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about The pollution in normal atmosphere is less than 0.01%. Due to leakage of methyl isocyanide (MIC) from a factory the pollution is increased to 20%. If every day 80% of the pollution in the atmosphere is neutralized, in how many days will the atmosphere become normal?a)6 daysb)3 daysc)4 daysd)None of theseCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Quant 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The pollution in normal atmosphere is less than 0.01%. Due to leakage of methyl isocyanide (MIC) from a factory the pollution is increased to 20%. If every day 80% of the pollution in the atmosphere is neutralized, in how many days will the atmosphere become normal?a)6 daysb)3 daysc)4 daysd)None of theseCorrect answer is option 'A'. Can you explain this answer?.
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