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50 cc of 0.04 M k2cr2o7 in acidic medium oxidises a sample of H2S gas to sulphur. Volume of 0.03 M kmno4 required to oxidise the same amount of h2s gas to sulphur in acidic medium is 10x.Here the value of X is?
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50 cc of 0.04 M k2cr2o7 in acidic medium oxidises a sample of H2S gas ...
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50 cc of 0.04 M k2cr2o7 in acidic medium oxidises a sample of H2S gas ...
The given information:
- 50 cc of 0.04 M K2Cr2O7 in acidic medium oxidizes a sample of H2S gas to sulphur.
- Volume of 0.03 M KMnO4 required to oxidize the same amount of H2S gas to sulphur in acidic medium is 10x.
To find:
The value of X.
Solution:
Step 1: Balancing the equations:
The reaction between K2Cr2O7 and H2S can be balanced as follows:
K2Cr2O7 + 8H2SO4 + 3H2S -> 2Cr2(SO4)3 + 2KHSO4 + 7H2O + 3S
The reaction between KMnO4 and H2S can be balanced as follows:
2KMnO4 + 8H2SO4 + 5H2S -> K2SO4 + 2MnSO4 + 8H2O + 5S
Step 2: Finding the moles of K2Cr2O7:
Moles = Volume (in L) * Molarity
Moles of K2Cr2O7 = 50 cc * 0.04 M = 0.002 moles
Step 3: Finding the moles of H2S:
From the balanced equation, we can see that 3 moles of H2S are required to react with 1 mole of K2Cr2O7.
Therefore, moles of H2S = 3 * 0.002 = 0.006 moles
Step 4: Finding the moles of KMnO4:
From the balanced equation, we can see that 5 moles of H2S are required to react with 2 moles of KMnO4.
Therefore, moles of KMnO4 = (5/2) * 0.006 = 0.015 moles
Step 5: Finding the volume of 0.03 M KMnO4:
Volume (in L) = Moles / Molarity = 0.015 / 0.03 = 0.5 L = 500 cc
Step 6: Finding the value of X:
Given that the volume of 0.03 M KMnO4 required is 10x the volume of 0.04 M K2Cr2O7,
500 cc (volume of KMnO4) = 10 * 50 cc (volume of K2Cr2O7)
X = 10
Answer:
The value of X is 10.
- 50 cc of 0.04 M K2Cr2O7 in acidic medium oxidizes a sample of H2S gas to sulphur.
- Volume of 0.03 M KMnO4 required to oxidize the same amount of H2S gas to sulphur in acidic medium is 10x.
To find:
The value of X.
Solution:
Step 1: Balancing the equations:
The reaction between K2Cr2O7 and H2S can be balanced as follows:
K2Cr2O7 + 8H2SO4 + 3H2S -> 2Cr2(SO4)3 + 2KHSO4 + 7H2O + 3S
The reaction between KMnO4 and H2S can be balanced as follows:
2KMnO4 + 8H2SO4 + 5H2S -> K2SO4 + 2MnSO4 + 8H2O + 5S
Step 2: Finding the moles of K2Cr2O7:
Moles = Volume (in L) * Molarity
Moles of K2Cr2O7 = 50 cc * 0.04 M = 0.002 moles
Step 3: Finding the moles of H2S:
From the balanced equation, we can see that 3 moles of H2S are required to react with 1 mole of K2Cr2O7.
Therefore, moles of H2S = 3 * 0.002 = 0.006 moles
Step 4: Finding the moles of KMnO4:
From the balanced equation, we can see that 5 moles of H2S are required to react with 2 moles of KMnO4.
Therefore, moles of KMnO4 = (5/2) * 0.006 = 0.015 moles
Step 5: Finding the volume of 0.03 M KMnO4:
Volume (in L) = Moles / Molarity = 0.015 / 0.03 = 0.5 L = 500 cc
Step 6: Finding the value of X:
Given that the volume of 0.03 M KMnO4 required is 10x the volume of 0.04 M K2Cr2O7,
500 cc (volume of KMnO4) = 10 * 50 cc (volume of K2Cr2O7)
X = 10
Answer:
The value of X is 10.
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50 cc of 0.04 M k2cr2o7 in acidic medium oxidises a sample of H2S gas to sulphur. Volume of 0.03 M kmno4 required to oxidise the same amount of h2s gas to sulphur in acidic medium is 10x.Here the value of X is?
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50 cc of 0.04 M k2cr2o7 in acidic medium oxidises a sample of H2S gas to sulphur. Volume of 0.03 M kmno4 required to oxidise the same amount of h2s gas to sulphur in acidic medium is 10x.Here the value of X is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 50 cc of 0.04 M k2cr2o7 in acidic medium oxidises a sample of H2S gas to sulphur. Volume of 0.03 M kmno4 required to oxidise the same amount of h2s gas to sulphur in acidic medium is 10x.Here the value of X is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 50 cc of 0.04 M k2cr2o7 in acidic medium oxidises a sample of H2S gas to sulphur. Volume of 0.03 M kmno4 required to oxidise the same amount of h2s gas to sulphur in acidic medium is 10x.Here the value of X is?.
50 cc of 0.04 M k2cr2o7 in acidic medium oxidises a sample of H2S gas to sulphur. Volume of 0.03 M kmno4 required to oxidise the same amount of h2s gas to sulphur in acidic medium is 10x.Here the value of X is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 50 cc of 0.04 M k2cr2o7 in acidic medium oxidises a sample of H2S gas to sulphur. Volume of 0.03 M kmno4 required to oxidise the same amount of h2s gas to sulphur in acidic medium is 10x.Here the value of X is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 50 cc of 0.04 M k2cr2o7 in acidic medium oxidises a sample of H2S gas to sulphur. Volume of 0.03 M kmno4 required to oxidise the same amount of h2s gas to sulphur in acidic medium is 10x.Here the value of X is?.
Solutions for 50 cc of 0.04 M k2cr2o7 in acidic medium oxidises a sample of H2S gas to sulphur. Volume of 0.03 M kmno4 required to oxidise the same amount of h2s gas to sulphur in acidic medium is 10x.Here the value of X is? in English & in Hindi are available as part of our courses for NEET.
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