NEET Exam > NEET Questions > 50 cc of 0.04 M k2cr2o7 in acidic medium oxid...
Start Learning for Free
50 cc of 0.04 M k2cr2o7 in acidic medium oxidises a sample of H2S gas to sulphur. Volume of 0.03 M kmno4 required to oxidise the same amount of h2s gas to sulphur in acidic medium is 10x.Here the value of X is?
Most Upvoted Answer
50 cc of 0.04 M k2cr2o7 in acidic medium oxidises a sample of H2S gas ...
Community Answer
50 cc of 0.04 M k2cr2o7 in acidic medium oxidises a sample of H2S gas ...
The given information:
- 50 cc of 0.04 M K2Cr2O7 in acidic medium oxidizes a sample of H2S gas to sulphur.
- Volume of 0.03 M KMnO4 required to oxidize the same amount of H2S gas to sulphur in acidic medium is 10x.
To find:
The value of X.
Solution:
Step 1: Balancing the equations:
The reaction between K2Cr2O7 and H2S can be balanced as follows:
K2Cr2O7 + 8H2SO4 + 3H2S -> 2Cr2(SO4)3 + 2KHSO4 + 7H2O + 3S
The reaction between KMnO4 and H2S can be balanced as follows:
2KMnO4 + 8H2SO4 + 5H2S -> K2SO4 + 2MnSO4 + 8H2O + 5S
Step 2: Finding the moles of K2Cr2O7:
Moles = Volume (in L) * Molarity
Moles of K2Cr2O7 = 50 cc * 0.04 M = 0.002 moles
Step 3: Finding the moles of H2S:
From the balanced equation, we can see that 3 moles of H2S are required to react with 1 mole of K2Cr2O7.
Therefore, moles of H2S = 3 * 0.002 = 0.006 moles
Step 4: Finding the moles of KMnO4:
From the balanced equation, we can see that 5 moles of H2S are required to react with 2 moles of KMnO4.
Therefore, moles of KMnO4 = (5/2) * 0.006 = 0.015 moles
Step 5: Finding the volume of 0.03 M KMnO4:
Volume (in L) = Moles / Molarity = 0.015 / 0.03 = 0.5 L = 500 cc
Step 6: Finding the value of X:
Given that the volume of 0.03 M KMnO4 required is 10x the volume of 0.04 M K2Cr2O7,
500 cc (volume of KMnO4) = 10 * 50 cc (volume of K2Cr2O7)
X = 10
Answer:
The value of X is 10.
- 50 cc of 0.04 M K2Cr2O7 in acidic medium oxidizes a sample of H2S gas to sulphur.
- Volume of 0.03 M KMnO4 required to oxidize the same amount of H2S gas to sulphur in acidic medium is 10x.
To find:
The value of X.
Solution:
Step 1: Balancing the equations:
The reaction between K2Cr2O7 and H2S can be balanced as follows:
K2Cr2O7 + 8H2SO4 + 3H2S -> 2Cr2(SO4)3 + 2KHSO4 + 7H2O + 3S
The reaction between KMnO4 and H2S can be balanced as follows:
2KMnO4 + 8H2SO4 + 5H2S -> K2SO4 + 2MnSO4 + 8H2O + 5S
Step 2: Finding the moles of K2Cr2O7:
Moles = Volume (in L) * Molarity
Moles of K2Cr2O7 = 50 cc * 0.04 M = 0.002 moles
Step 3: Finding the moles of H2S:
From the balanced equation, we can see that 3 moles of H2S are required to react with 1 mole of K2Cr2O7.
Therefore, moles of H2S = 3 * 0.002 = 0.006 moles
Step 4: Finding the moles of KMnO4:
From the balanced equation, we can see that 5 moles of H2S are required to react with 2 moles of KMnO4.
Therefore, moles of KMnO4 = (5/2) * 0.006 = 0.015 moles
Step 5: Finding the volume of 0.03 M KMnO4:
Volume (in L) = Moles / Molarity = 0.015 / 0.03 = 0.5 L = 500 cc
Step 6: Finding the value of X:
Given that the volume of 0.03 M KMnO4 required is 10x the volume of 0.04 M K2Cr2O7,
500 cc (volume of KMnO4) = 10 * 50 cc (volume of K2Cr2O7)
X = 10
Answer:
The value of X is 10.
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
|
Explore Courses for NEET exam
|
|
Similar NEET Doubts
Top Courses for NEETView all
50 cc of 0.04 M k2cr2o7 in acidic medium oxidises a sample of H2S gas to sulphur. Volume of 0.03 M kmno4 required to oxidise the same amount of h2s gas to sulphur in acidic medium is 10x.Here the value of X is?
Question Description
50 cc of 0.04 M k2cr2o7 in acidic medium oxidises a sample of H2S gas to sulphur. Volume of 0.03 M kmno4 required to oxidise the same amount of h2s gas to sulphur in acidic medium is 10x.Here the value of X is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 50 cc of 0.04 M k2cr2o7 in acidic medium oxidises a sample of H2S gas to sulphur. Volume of 0.03 M kmno4 required to oxidise the same amount of h2s gas to sulphur in acidic medium is 10x.Here the value of X is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 50 cc of 0.04 M k2cr2o7 in acidic medium oxidises a sample of H2S gas to sulphur. Volume of 0.03 M kmno4 required to oxidise the same amount of h2s gas to sulphur in acidic medium is 10x.Here the value of X is?.
50 cc of 0.04 M k2cr2o7 in acidic medium oxidises a sample of H2S gas to sulphur. Volume of 0.03 M kmno4 required to oxidise the same amount of h2s gas to sulphur in acidic medium is 10x.Here the value of X is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 50 cc of 0.04 M k2cr2o7 in acidic medium oxidises a sample of H2S gas to sulphur. Volume of 0.03 M kmno4 required to oxidise the same amount of h2s gas to sulphur in acidic medium is 10x.Here the value of X is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 50 cc of 0.04 M k2cr2o7 in acidic medium oxidises a sample of H2S gas to sulphur. Volume of 0.03 M kmno4 required to oxidise the same amount of h2s gas to sulphur in acidic medium is 10x.Here the value of X is?.
Solutions for 50 cc of 0.04 M k2cr2o7 in acidic medium oxidises a sample of H2S gas to sulphur. Volume of 0.03 M kmno4 required to oxidise the same amount of h2s gas to sulphur in acidic medium is 10x.Here the value of X is? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of 50 cc of 0.04 M k2cr2o7 in acidic medium oxidises a sample of H2S gas to sulphur. Volume of 0.03 M kmno4 required to oxidise the same amount of h2s gas to sulphur in acidic medium is 10x.Here the value of X is? defined & explained in the simplest way possible. Besides giving the explanation of
50 cc of 0.04 M k2cr2o7 in acidic medium oxidises a sample of H2S gas to sulphur. Volume of 0.03 M kmno4 required to oxidise the same amount of h2s gas to sulphur in acidic medium is 10x.Here the value of X is?, a detailed solution for 50 cc of 0.04 M k2cr2o7 in acidic medium oxidises a sample of H2S gas to sulphur. Volume of 0.03 M kmno4 required to oxidise the same amount of h2s gas to sulphur in acidic medium is 10x.Here the value of X is? has been provided alongside types of 50 cc of 0.04 M k2cr2o7 in acidic medium oxidises a sample of H2S gas to sulphur. Volume of 0.03 M kmno4 required to oxidise the same amount of h2s gas to sulphur in acidic medium is 10x.Here the value of X is? theory, EduRev gives you an
ample number of questions to practice 50 cc of 0.04 M k2cr2o7 in acidic medium oxidises a sample of H2S gas to sulphur. Volume of 0.03 M kmno4 required to oxidise the same amount of h2s gas to sulphur in acidic medium is 10x.Here the value of X is? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup