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Standard entropy of X2, Y2 and XY3 are 60, 40 and 50 JK-1 mol-1 respectively. For a given reaction, to be in equilibrium, the temperature will bea)1000 Kb)1250 Kc)500 Kd)750 KCorrect answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Standard entropy of X2, Y2 and XY3 are 60, 40 and 50 JK-1 mol-1 respectively. For a given reaction, to be in equilibrium, the temperature will bea)1000 Kb)1250 Kc)500 Kd)750 KCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Standard entropy of X2, Y2 and XY3 are 60, 40 and 50 JK-1 mol-1 respectively. For a given reaction, to be in equilibrium, the temperature will bea)1000 Kb)1250 Kc)500 Kd)750 KCorrect answer is option 'D'. Can you explain this answer?.

Solutions for Standard entropy of X2, Y2 and XY3 are 60, 40 and 50 JK-1 mol-1 respectively. For a given reaction, to be in equilibrium, the temperature will bea)1000 Kb)1250 Kc)500 Kd)750 KCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.

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