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The heavenly body is receding from earth, such that the fractional change √\(lamda) in is 1 then its velocity is 1) c 2) 3c/5 3) c/5 4) 2c/5?
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The heavenly body is receding from earth, such that the fractional cha...
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The heavenly body is receding from earth, such that the fractional cha...
Answer:
Explanation:
The question is asking about the velocity of a heavenly body, which is receding from the earth. The fractional change in wavelength, √(lambda), is given as 1. We need to calculate the velocity of the heavenly body.
The given formula is,
(λ - λ0)/λ0 = √(v^2/c^2)/(1-v^2/c^2)
where λ is the wavelength of the light emitted by the heavenly body, λ0 is the wavelength of the same light when observed on the earth, v is the velocity of the heavenly body and c is the speed of light.
We are given √(λ) = 1, which implies λ/λ0 = 2. Therefore,
(λ - λ0)/λ0 = 1
Substituting the values in the formula, we get
1 = √(v^2/c^2)/(1-v^2/c^2)
Squaring on both sides, we get
1 - v^2/c^2 = v^2/c^2
2v^2/c^2 = 1
v^2 = c^2/2
v = c/√2
v = c/1.414
v = 0.707c
Therefore, the velocity of the heavenly body is 0.707 times the speed of light.
Answer: Option 3) c/5.
Explanation:
The question is asking about the velocity of a heavenly body, which is receding from the earth. The fractional change in wavelength, √(lambda), is given as 1. We need to calculate the velocity of the heavenly body.
The given formula is,
(λ - λ0)/λ0 = √(v^2/c^2)/(1-v^2/c^2)
where λ is the wavelength of the light emitted by the heavenly body, λ0 is the wavelength of the same light when observed on the earth, v is the velocity of the heavenly body and c is the speed of light.
We are given √(λ) = 1, which implies λ/λ0 = 2. Therefore,
(λ - λ0)/λ0 = 1
Substituting the values in the formula, we get
1 = √(v^2/c^2)/(1-v^2/c^2)
Squaring on both sides, we get
1 - v^2/c^2 = v^2/c^2
2v^2/c^2 = 1
v^2 = c^2/2
v = c/√2
v = c/1.414
v = 0.707c
Therefore, the velocity of the heavenly body is 0.707 times the speed of light.
Answer: Option 3) c/5.
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The heavenly body is receding from earth, such that the fractional change √\(lamda) in is 1 then its velocity is 1) c 2) 3c/5 3) c/5 4) 2c/5?
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The heavenly body is receding from earth, such that the fractional change √\(lamda) in is 1 then its velocity is 1) c 2) 3c/5 3) c/5 4) 2c/5? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The heavenly body is receding from earth, such that the fractional change √\(lamda) in is 1 then its velocity is 1) c 2) 3c/5 3) c/5 4) 2c/5? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The heavenly body is receding from earth, such that the fractional change √\(lamda) in is 1 then its velocity is 1) c 2) 3c/5 3) c/5 4) 2c/5?.
The heavenly body is receding from earth, such that the fractional change √\(lamda) in is 1 then its velocity is 1) c 2) 3c/5 3) c/5 4) 2c/5? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The heavenly body is receding from earth, such that the fractional change √\(lamda) in is 1 then its velocity is 1) c 2) 3c/5 3) c/5 4) 2c/5? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The heavenly body is receding from earth, such that the fractional change √\(lamda) in is 1 then its velocity is 1) c 2) 3c/5 3) c/5 4) 2c/5?.
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