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A video transmission system transmits 625 picture frames per second each frame consist of 400 x 400 pixel grid
with 64 intensity levels per pixel. The data rate (in Gbps) of the system is
__________________
    Correct answer is between '6.2,6.5'. Can you explain this answer?
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    A video transmission system transmits 625 picture frames per second ea...
    Rate = 625 × 4002 × 64 = 6.4 Gbps
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    Most Upvoted Answer
    A video transmission system transmits 625 picture frames per second ea...
    The data rate of a video transmission system can be calculated by considering the number of pixels, the number of intensity levels, and the frame rate. Let's break down the calculation step by step.

    Step 1: Determine the number of pixels
    Each frame consists of a 400x400 pixel grid, which means there are 400 * 400 = 160,000 pixels in each frame.

    Step 2: Determine the number of bits per pixel
    Since there are 64 intensity levels per pixel, we can represent each intensity level using 6 bits (2^6 = 64). Therefore, the number of bits per pixel is 6.

    Step 3: Calculate the number of bits per frame
    To calculate the number of bits per frame, we multiply the number of pixels by the number of bits per pixel:
    Bits per frame = Number of pixels * Bits per pixel
    Bits per frame = 160,000 * 6 = 960,000 bits

    Step 4: Determine the frame rate
    The frame rate of the video transmission system is given as 625 frames per second.

    Step 5: Calculate the data rate
    To calculate the data rate, we multiply the number of bits per frame by the frame rate:
    Data rate = Bits per frame * Frame rate
    Data rate = 960,000 bits * 625 frames per second

    To convert the data rate to Gbps (Gigabits per second), we divide the data rate by 10^9:
    Data rate (Gbps) = (960,000 * 625) / 10^9

    Final calculation:
    Data rate (Gbps) = 600 Gbps

    Therefore, the data rate of the video transmission system is 600 Gbps. Since the correct answer is between 6.2 Gbps and 6.5 Gbps, it seems there is an error in the calculation or the provided answer range.
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    Consider a simple communication system where multiple nodes are connected by a shared broadcast medium (like Ethernet or wireless). The nodes in the system use the following carrier-sense based medium access protocol. A node that receives a packet to transmit will carrier-sense the medium for 5 units of time. If the node does not detect any other transmission in this duration, it starts transmitting its packet in the next time unit. If the node detects another transmission, it waits until this other transmission finishes, and then begins to carrier-sense for 5 time units again. Once they start to transmit, nodes do not perform any collision detection and continue transmission even if a collision occurs. All transmissions last for 20 units of time. Assume that the transmission signal travels at the speed of 10 meters per unit time in the medium.Assume that the system has two nodes P and Q, located at a distance d meters from each other. P starts transmitting a packet at time t=0 after successfully completing its carrier-sense phase. Node Q has a packet to transmit at time t=0 and begins to carrier-sense the medium. The maximum distance d (in meters, rounded to the closest integer) that allows Q to successfully avoid a collision between its proposed transmission and P’s ongoing transmission is _____. Correct answer is '50 to 50'. Can you explain this answer?

    A video transmission system transmits 625 picture frames per second each frame consist of 400x 400pixel gridwith 64 intensity levels per pixel. The data rate (in Gbps) of the system is__________________Correct answer is between '6.2,6.5'. Can you explain this answer?
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