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The ratio of mass percent of C and H of an organic compound (CyHyOz) is 6: 1. If one molecule of the above compound (CxHyOz) contains half as much oxygen as required to burn one molecule of compound CxHy completely to CO2 and H20. The empirical formula of compound CxHyOz is- (A)C2H4O3 (B) C3H6O3 (C)C2H4O (D)C3H4O2? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The ratio of mass percent of C and H of an organic compound (CyHyOz) is 6: 1. If one molecule of the above compound (CxHyOz) contains half as much oxygen as required to burn one molecule of compound CxHy completely to CO2 and H20. The empirical formula of compound CxHyOz is- (A)C2H4O3 (B) C3H6O3 (C)C2H4O (D)C3H4O2? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The ratio of mass percent of C and H of an organic compound (CyHyOz) is 6: 1. If one molecule of the above compound (CxHyOz) contains half as much oxygen as required to burn one molecule of compound CxHy completely to CO2 and H20. The empirical formula of compound CxHyOz is- (A)C2H4O3 (B) C3H6O3 (C)C2H4O (D)C3H4O2?.

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