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Using mass (M), length (L), time (T) and current (A) as fundamental quantities, the dimensions of permeability is
- a)[M⁻1 LT-2 A]
- b)[ML2 T-2 A⁻1]
- c)[MLT-2 A-2]
- d)[MLT⁻1 A⁻1]
Correct answer is option 'C'. Can you explain this answer?
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Dimensions of Permeability
The permeability of a substance is defined as its ability to allow magnetic lines of force to pass through it. It is expressed in terms of dimensions, which are derived from the fundamental quantities. The dimensions of permeability can be determined by using the method of dimensional analysis.
Fundamental Quantities and Their Dimensions
- Mass (M) - dimension [M]
- Length (L) - dimension [L]
- Time (T) - dimension [T]
- Current (A) - dimension [A]
Dimensions of Permeability
Using the above fundamental quantities, the dimensions of permeability can be determined as follows:
- Magnetic permeability (μ) = magnetic field intensity (H) / magnetic flux density (B)
- Dimensions of magnetic field intensity (H) = [L]/[T] = [LT-1]
- Dimensions of magnetic flux density (B) = [M]/[LT-2] = [MLT-2]
- Dimensions of magnetic permeability (μ) = [LT-1]/[MLT-2] = [MLT-2 T-1 A-2]
Therefore, the correct option is (c) [MLT-2 A-2].
The permeability of a substance is defined as its ability to allow magnetic lines of force to pass through it. It is expressed in terms of dimensions, which are derived from the fundamental quantities. The dimensions of permeability can be determined by using the method of dimensional analysis.
Fundamental Quantities and Their Dimensions
- Mass (M) - dimension [M]
- Length (L) - dimension [L]
- Time (T) - dimension [T]
- Current (A) - dimension [A]
Dimensions of Permeability
Using the above fundamental quantities, the dimensions of permeability can be determined as follows:
- Magnetic permeability (μ) = magnetic field intensity (H) / magnetic flux density (B)
- Dimensions of magnetic field intensity (H) = [L]/[T] = [LT-1]
- Dimensions of magnetic flux density (B) = [M]/[LT-2] = [MLT-2]
- Dimensions of magnetic permeability (μ) = [LT-1]/[MLT-2] = [MLT-2 T-1 A-2]
Therefore, the correct option is (c) [MLT-2 A-2].
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Using mass (M), length (L), time (T) and current (A) as fundamental quantities, the dimensions of permeability isa)[M1LT-2 A]b)[ML2T-2 A1]c)[MLT-2 A-2]d)[MLT1A1]Correct answer is option 'C'. Can you explain this answer?
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Using mass (M), length (L), time (T) and current (A) as fundamental quantities, the dimensions of permeability isa)[M1LT-2 A]b)[ML2T-2 A1]c)[MLT-2 A-2]d)[MLT1A1]Correct answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Using mass (M), length (L), time (T) and current (A) as fundamental quantities, the dimensions of permeability isa)[M1LT-2 A]b)[ML2T-2 A1]c)[MLT-2 A-2]d)[MLT1A1]Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Using mass (M), length (L), time (T) and current (A) as fundamental quantities, the dimensions of permeability isa)[M1LT-2 A]b)[ML2T-2 A1]c)[MLT-2 A-2]d)[MLT1A1]Correct answer is option 'C'. Can you explain this answer?.
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