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A wagon weighing 1000 kg is moving with velocity of 50 km/h on smooth horizontal rails. A mass of 250 kg is deopped into it. The velocity with which it moves now is
  • a)
    112.5 km/h
  • b)
    20 km/h
  • c)
    40 km/h
  • d)
    50 km/h
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A wagon weighing 1000 kg is moving with velocity of 50 km/h on smooth ...
Initial linear momentum of the system  Pi​=mv=1000×50=5×104 kg km/h

Let the final velocity (wagon+ mass dropped) system be V.

Final linear momentum of the system  Pf​=(m+M)V=(1000+250)V=1250V

Using conservation of linear momentum,  Pf​=Pi​

∴  1250V=5×104

⟹  V=12505×104​=40 km/h
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Community Answer
A wagon weighing 1000 kg is moving with velocity of 50 km/h on smooth ...
Initial Situation:
- Wagon weight: 1000 kg
- Initial velocity: 50 km/h

When the mass is dropped:
- Additional mass dropped: 250 kg
- Total mass after dropping: 1000 kg + 250 kg = 1250 kg

Conservation of Momentum:
- Before dropping the mass, the momentum of the system was 1000 kg * 50 km/h = 50000 kg km/h
- After dropping the mass, the momentum of the system will remain the same
- Let the final velocity of the system be V km/h

Using the principle of conservation of momentum:
- Initial momentum = Final momentum
- 1000 kg * 50 km/h = 1250 kg * V km/h
- V = (1000 * 50) / 1250 = 40 km/h
Therefore, the velocity with which the wagon moves after dropping the mass is 40 km/h. Hence, option C is correct.
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A wagon weighing 1000 kg is moving with velocity of 50 km/h on smooth horizontal rails. A mass of 250 kg is deopped into it. The velocity with which it moves now isa)112.5 km/hb)20 km/hc)40 km/hd)50 km/hCorrect answer is option 'C'. Can you explain this answer?
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