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A wagon weighing 1000 kg is moving with velocity of 50 km/h on smooth horizontal rails. A mass of 250 kg is deopped into it. The velocity with which it moves now is
- a)112.5 km/h
- b)20 km/h
- c)40 km/h
- d)50 km/h
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
A wagon weighing 1000 kg is moving with velocity of 50 km/h on smooth ...
Initial linear momentum of the system Pi=mv=1000×50=5×104 kg km/h
Let the final velocity (wagon+ mass dropped) system be V.
Final linear momentum of the system Pf=(m+M)V=(1000+250)V=1250V
Using conservation of linear momentum, Pf=Pi
∴ 1250V=5×104
⟹ V=12505×104=40 km/h
Let the final velocity (wagon+ mass dropped) system be V.
Final linear momentum of the system Pf=(m+M)V=(1000+250)V=1250V
Using conservation of linear momentum, Pf=Pi
∴ 1250V=5×104
⟹ V=12505×104=40 km/h
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A wagon weighing 1000 kg is moving with velocity of 50 km/h on smooth ...
Initial Situation:
- Wagon weight: 1000 kg
- Initial velocity: 50 km/h
When the mass is dropped:
- Additional mass dropped: 250 kg
- Total mass after dropping: 1000 kg + 250 kg = 1250 kg
Conservation of Momentum:
- Before dropping the mass, the momentum of the system was 1000 kg * 50 km/h = 50000 kg km/h
- After dropping the mass, the momentum of the system will remain the same
- Let the final velocity of the system be V km/h
Using the principle of conservation of momentum:
- Initial momentum = Final momentum
- 1000 kg * 50 km/h = 1250 kg * V km/h
- V = (1000 * 50) / 1250 = 40 km/h
Therefore, the velocity with which the wagon moves after dropping the mass is 40 km/h. Hence, option C is correct.
- Wagon weight: 1000 kg
- Initial velocity: 50 km/h
When the mass is dropped:
- Additional mass dropped: 250 kg
- Total mass after dropping: 1000 kg + 250 kg = 1250 kg
Conservation of Momentum:
- Before dropping the mass, the momentum of the system was 1000 kg * 50 km/h = 50000 kg km/h
- After dropping the mass, the momentum of the system will remain the same
- Let the final velocity of the system be V km/h
Using the principle of conservation of momentum:
- Initial momentum = Final momentum
- 1000 kg * 50 km/h = 1250 kg * V km/h
- V = (1000 * 50) / 1250 = 40 km/h
Therefore, the velocity with which the wagon moves after dropping the mass is 40 km/h. Hence, option C is correct.
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A wagon weighing 1000 kg is moving with velocity of 50 km/h on smooth horizontal rails. A mass of 250 kg is deopped into it. The velocity with which it moves now isa)112.5 km/hb)20 km/hc)40 km/hd)50 km/hCorrect answer is option 'C'. Can you explain this answer?
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A wagon weighing 1000 kg is moving with velocity of 50 km/h on smooth horizontal rails. A mass of 250 kg is deopped into it. The velocity with which it moves now isa)112.5 km/hb)20 km/hc)40 km/hd)50 km/hCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A wagon weighing 1000 kg is moving with velocity of 50 km/h on smooth horizontal rails. A mass of 250 kg is deopped into it. The velocity with which it moves now isa)112.5 km/hb)20 km/hc)40 km/hd)50 km/hCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A wagon weighing 1000 kg is moving with velocity of 50 km/h on smooth horizontal rails. A mass of 250 kg is deopped into it. The velocity with which it moves now isa)112.5 km/hb)20 km/hc)40 km/hd)50 km/hCorrect answer is option 'C'. Can you explain this answer?.
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