To solve this problem, we can use the concept of permutations and combinations.

Permutations:
In this problem, we need to find the number of ways to arrange the 5 rings on 3 fingers. Since the order in which the rings are worn on each finger matters, we need to use the concept of permutations.

Permutations formula:
If there are 'n' objects to be arranged in 'r' places and the order matters, the number of permutations is given by:
P(n, r) = n! / (n - r)!

Combinations:
In this problem, we also need to consider the combinations of choosing which fingers will wear the rings. Since the order of choosing the fingers does not matter, we need to use the concept of combinations.

Combinations formula:
If there are 'n' objects to be chosen and 'r' objects are chosen at a time, the number of combinations is given by:
C(n, r) = n! / (r! * (n - r)!)

Solution:
To solve the problem, we need to find the number of permutations for the arrangement of rings on fingers and the number of combinations for choosing the fingers.

Number of permutations:
There are 5 rings to be worn on 3 fingers. We can arrange the rings on fingers in the following ways:
- 3 rings on one finger, 1 ring on another finger, and 1 ring on the remaining finger.
- 2 rings on one finger and 1 ring on each of the other two fingers.
- 1 ring on one finger and 2 rings on each of the other two fingers.

For the first case, we have 3 choices for the finger to wear 3 rings, and then 2 choices for the finger to wear 1 ring. Once we have chosen the fingers, we can arrange the rings on them in 3! = 6 ways. Therefore, the number of permutations for the first case is 3 * 2 * 6 = 36.

For the second case, we have 3 choices for the finger to wear 2 rings, and then 2 choices for the finger to wear 1 ring. Once we have chosen the fingers, we can arrange the rings on them in 3! = 6 ways. Therefore, the number of permutations for the second case is 3 * 2 * 6 = 36.

For the third case, we have 3 choices for the finger to wear 1 ring, and then 2 choices for the other finger to wear 2 rings. Once we have chosen the fingers, we can arrange the rings on them in 3! = 6 ways. Therefore, the number of permutations for the third case is 3 * 2 * 6 = 36.

Therefore, the total number of permutations for the arrangement of rings on fingers is 36 + 36 + 36 = 108.

Number of combinations:
There are 3 fingers to choose from to wear the rings. We need to choose 3 fingers from these 3 fingers. Therefore, the number of combinations is C(3, 3) = 3! / (3! * (3 - 3)!) = 1.

Total number of ways:
To find the total number of ways, we multiply the number of permutations by the number of combinations:
Total number of ways = Number of permutations * Number of combinations
= 108