🥇1 - 27/4
🥈2 - 27/6
🥉3 - 27/8.

===>
🏅🏅🏅🏅🏅🏅🏅🏅🏅🏅🏅🏅🏅🏅🏅🏅🏅🏅🏅🏅🏅🏅 4 , 6 and 8 are the answers

Understanding the Problem
To solve the problem of determining by what number 27 can be divided to yield a remainder of 3, we can employ the concept of division in mathematics.
Division and Remainder Concept
When a number \( a \) is divided by another number \( b \), it can be expressed as:
\[ a = b \times q + r \]
Where:
- \( a \) is the dividend (27 in this case)
- \( b \) is the divisor (the number we want to find)
- \( q \) is the quotient
- \( r \) is the remainder (which is 3)
Setting Up the Equation
In our case, we can set up the equation as follows:
\[ 27 = b \times q + 3 \]
To isolate \( b \), we can rearrange the equation:
\[ b \times q = 27 - 3 \]
\[ b \times q = 24 \]
Finding Possible Divisors
Now, we need to find values for \( b \) that will satisfy \( b \times q = 24 \). The possible positive integer divisors of 24 (which are the candidates for \( b \)) are:
- 1
- 2
- 3
- 4
- 6
- 8
- 12
- 24
For each of these divisors, we can find the corresponding quotient \( q \):
- If \( b = 1 \), \( q = 24 \)
- If \( b = 2 \), \( q = 12 \)
- If \( b = 3 \), \( q = 8 \)
- If \( b = 4 \), \( q = 6 \)
- If \( b = 6 \), \( q = 4 \)
- If \( b = 8 \), \( q = 3 \)
- If \( b = 12 \), \( q = 2 \)
- If \( b = 24 \), \( q = 1 \)
Conclusion
Any of the divisors listed above (1, 2, 3, 4, 6, 8, 12, or 24) can be used to divide 27 and yield a remainder of 3.