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A bag contains 8 blue and 7 green balls. A ball is drawn out of it and put back in the bag. Then a ball is drawn again. What is the probability that both the balls are green?
- a)36/225
- b)48/221
- c)49/225
- d)40/221
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
A bag contains 8 blue and 7 green balls. A ball is drawn out of it and...
To solve this problem, we need to determine the probability of drawing a green ball twice in a row.
Number of green balls = 7
Total number of balls = 8 (blue) + 7 (green) = 15
Probability of drawing a green ball on the first draw = Number of green balls / Total number of balls
= 7 / 15
Since the ball is put back in the bag, the number of green balls and total number of balls remain the same.
Probability of drawing a green ball on the second draw = Number of green balls / Total number of balls
= 7 / 15
To find the probability of both balls being green, we need to multiply the probabilities of the two draws.
Probability of both balls being green = Probability of first green ball * Probability of second green ball
= (7/15) * (7/15)
= 49/225
Therefore, the correct answer is option 'C' (49/225).
Number of green balls = 7
Total number of balls = 8 (blue) + 7 (green) = 15
Probability of drawing a green ball on the first draw = Number of green balls / Total number of balls
= 7 / 15
Since the ball is put back in the bag, the number of green balls and total number of balls remain the same.
Probability of drawing a green ball on the second draw = Number of green balls / Total number of balls
= 7 / 15
To find the probability of both balls being green, we need to multiply the probabilities of the two draws.
Probability of both balls being green = Probability of first green ball * Probability of second green ball
= (7/15) * (7/15)
= 49/225
Therefore, the correct answer is option 'C' (49/225).
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