Finding the Atomic Weight of X in Compound XnO

Given information:
- Vapour density of XnO is 14
- Volume of X is half that of oxygen

Formula:
- Vapour density = (molecular weight of compound) / 2
- Molecular weight of compound = (atomic weight of X * n) + atomic weight of oxygen

Solution:

1. Calculate the molecular weight of XnO
- Vapour density = (molecular weight of compound) / 2
- 14 = (atomic weight of X * n + atomic weight of oxygen) / 2
- 28 = atomic weight of X * n + atomic weight of oxygen

2. Calculate the volume ratio of X to oxygen
- Volume of X / Volume of oxygen = 1/2
- Since oxygen is diatomic, we use its molecular weight of 32 instead of its atomic weight of 16
- (atomic weight of X * n) / (32 * 1/2) = 1/2
- atomic weight of X * n = 16

3. Use simultaneous equations to solve for atomic weight of X and atomic weight of oxygen
- 28 = atomic weight of X * n + atomic weight of oxygen
- atomic weight of X * n = 16
- n = 16 / atomic weight of X
- Substitute n into the first equation
- 28 = atomic weight of X * (16 / atomic weight of X) + atomic weight of oxygen
- 28 = 16 + atomic weight of oxygen
- atomic weight of oxygen = 12

4. Calculate atomic weight of X
- 28 = atomic weight of X * (16 / atomic weight of X) + 12
- 16 = atomic weight of X
- Therefore, the atomic weight of X is 16.

Conclusion:
- The atomic weight of X in compound XnO is 16.

Molecular wt. = Vapour density × 2
Molecular wt. = 14 × 2 = 28
Atomic wt of O = 16
Atomic wt. of Xn = 28 - 16 = 12