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If a,b (a≠b), are the real roots of the equation (k + 1)(x+ x + 1)+ (k - 1)(x+ x+ 1) = 0, k ≠ 1, 0. 
Then the product of the roots is
  • a)
    (k + 1)/(k - 1)
  • b)
    1
  • c)
    (k2 + 1)/(k2 - 1)
  • d)
    3
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
If a,b(a≠b),are the real roots of the equation(k+ 1)(x2+ x+ 1)2+(k ...
Since the equation (x+  x + 1) = 0 . oes not have any real roots, the roots of the original equation will be the root of the equation (kx2 + x + k) = 0
 
Hence product of the roots = k/k = 1
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If a,b(a≠b),are the real roots of the equation(k+ 1)(x2+ x+ 1)2+(k ...
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If a,b(a≠b),are the real roots of the equation(k+ 1)(x2+ x+ 1)2+(k - 1)(x4+ x2+ 1)= 0, k≠1, 0.Then the product of the roots isa)(k + 1)/(k - 1)b)1c)(k2 + 1)/(k2 - 1)d)3Correct answer is option 'B'. Can you explain this answer?
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