Hybridization = Number of sigma- electrons = 2+2(negative ion)/2 = 2 =sp.The pair of electron in the given carbanion, CH3C=-C-, is presnt in sp orbital.(=- is triple bond)

The electron pair in the carbanion CH3C=-C- is present in the sp² orbital. To understand why this is the case, we need to examine the hybridization of the carbon atoms in this molecule.

Hybridization refers to the mixing of atomic orbitals to form new hybrid orbitals that are used for bonding. In this case, the carbon atoms in the carbanion undergo hybridization to accommodate the triple bond between them.

1. Hybridization of carbon atoms:
- The carbon atom attached to the methyl group (CH3) undergoes sp³ hybridization. This means that one s orbital and three p orbitals (px, py, and pz) combine to form four sp³ hybrid orbitals.
- The other carbon atom, participating in the triple bond, undergoes sp hybridization. Here, one s orbital and one p orbital (pz) combine to form two sp hybrid orbitals.

2. Formation of σ bonds:
- The sp³ hybridized carbon atom forms sigma (σ) bonds with the attached hydrogens and the adjacent carbon atom. These sigma bonds are formed by overlapping of the sp³ hybrid orbitals with the 1s orbitals of the hydrogens and the sp³ hybrid orbitals of the adjacent carbon atom.
- The sp hybridized carbon atom forms sigma (σ) bonds with the attached hydrogen and the other carbon atom. These sigma bonds are formed by overlapping of the sp hybrid orbitals with the 1s orbital of the hydrogen and the sp hybrid orbitals of the other carbon atom.

3. Formation of π bond:
- The triple bond between the two carbon atoms consists of one sigma (σ) bond and two pi (π) bonds.
- The pi (π) bonds are formed by the overlap of the unhybridized p orbitals (px and py) of the carbon atoms.

4. Electron pair in the sp² orbital:
- The electron pair in the carbanion is present in the unhybridized p orbital (pz) of the sp² hybridized carbon atom.
- This unhybridized p orbital is perpendicular to the plane formed by the sigma bonds and the other p orbital (px or py) that participates in the pi (π) bond.

In summary, the pair of electrons in the carbanion CH3C=-C- is present in the sp² orbital. This orbital is formed by the hybridization of one s orbital and two p orbitals (px and py) of the carbon atom participating in the triple bond. The unhybridized p orbital (pz) of this sp² hybridized carbon atom accommodates the electron pair, allowing for the formation of the triple bond and the overall stability of the carbanion.

hybridization nikalne ka asaan tarika haii kii no. of sigma bond count kar le ....agar 2 sigma aaya to sp..... aur 2 sigma aaya to sp2 so on......