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In a guitar, two strings A and B made of same material are slightly out of tune and produce beats of frequency 6 Hz. When tension in B is slightly decreased, the beat frequency increases to 7 Hz. If the frequency of A is 530 Hz, the original frequency of B will be :
  • a)
    536 Hz
  • b)
    537 Hz
  • c)
    523 Hz
  • d)
    524 Hz
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
In a guitar, two strings A and B made of same material are slightly ou...
Frequency of A = fA = 530 Hz, fB = ?
|fA – fB | = 6, given

So fB = 524 Hz
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Most Upvoted Answer
In a guitar, two strings A and B made of same material are slightly ou...
Given:
Frequency of string A = 530 Hz
Frequency of beats produced = 6 Hz
New frequency of beats produced when tension in string B is decreased = 7 Hz

To find:
Original frequency of string B

Solution:
Let the frequency of string B be x Hz

Frequency of beats produced = |530 - x| Hz
Given that the difference in frequency between the two strings is very small. Therefore, we can assume that the frequency of each string is nearly equal to the average of their frequencies.

∴ Average frequency of A and B = (530 + x)/2

Given that beats of frequency 6 Hz are produced when both strings are played together.
∴ |530 - x| = 6
⇒ 530 - x = 6 or x - 530 = 6
⇒ x = 524 or x = 536

Now, the tension in string B is slightly decreased, and the frequency of beats produced is 7 Hz.

When the tension in string B is decreased, its frequency decreases.
∴ The original frequency of string B must have been greater than 524 Hz.

Hence, the original frequency of string B = 524 Hz.
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In a guitar, two strings A and B made of same material are slightly out of tune and produce beats of frequency 6 Hz. When tension in B is slightly decreased, the beat frequency increases to 7 Hz. If the frequency of A is 530 Hz, the original frequency of B will be :a)536 Hzb)537 Hzc)523 Hzd)524 HzCorrect answer is option 'D'. Can you explain this answer?
Question Description
In a guitar, two strings A and B made of same material are slightly out of tune and produce beats of frequency 6 Hz. When tension in B is slightly decreased, the beat frequency increases to 7 Hz. If the frequency of A is 530 Hz, the original frequency of B will be :a)536 Hzb)537 Hzc)523 Hzd)524 HzCorrect answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In a guitar, two strings A and B made of same material are slightly out of tune and produce beats of frequency 6 Hz. When tension in B is slightly decreased, the beat frequency increases to 7 Hz. If the frequency of A is 530 Hz, the original frequency of B will be :a)536 Hzb)537 Hzc)523 Hzd)524 HzCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a guitar, two strings A and B made of same material are slightly out of tune and produce beats of frequency 6 Hz. When tension in B is slightly decreased, the beat frequency increases to 7 Hz. If the frequency of A is 530 Hz, the original frequency of B will be :a)536 Hzb)537 Hzc)523 Hzd)524 HzCorrect answer is option 'D'. Can you explain this answer?.
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