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Which one of the following is the strongest oxidising agent a)BrO3^-/Br^2+, E^o=+1.50 b)Fe^3+/Fe^2+, E^o=+0.76 c)MnO4^-/Mn^2+,E^o=+1.52 d)Cr2O7^2-/Cr^3+,E^o=+1.33
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Which one of the following is the strongest oxidising agent a)BrO3^-/B...
Strongest Oxidizing Agent

Among the given options, the strongest oxidizing agent is MnO4^-/Mn^2 with an E^o value of 1.52.

Explanation

To determine the strongest oxidizing agent, we need to look at the reduction potential values. The higher the reduction potential, the stronger the oxidizing agent.

BrO3^-/Br^2

The reduction potential for this reaction is 1.50, which is lower than MnO4^-/Mn^2. Hence, it is not the strongest oxidizing agent.

Fe^3 /Fe^2

The reduction potential for this reaction is 0.76, which is lower than both MnO4^-/Mn^2 and BrO3^-/Br^2. Hence, it is not the strongest oxidizing agent.

Cr2O7^2-/Cr^3

The reduction potential for this reaction is 1.33, which is higher than Fe^3 /Fe^2 but lower than MnO4^-/Mn^2. Hence, it is not the strongest oxidizing agent.

MnO4^-/Mn^2

The reduction potential for this reaction is 1.52, which is the highest among all the given options. Hence, it is the strongest oxidizing agent.

Conclusion

In conclusion, MnO4^-/Mn^2 is the strongest oxidizing agent among the given options.
Community Answer
Which one of the following is the strongest oxidising agent a)BrO3^-/B...
answer is c strong oxidizing is that who will reduce other and oxidises itself and also acc to electrochemical series
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Read the following statements carefully.(i) According to a convention, the cell potential of hydrogen electrode (S.H.E.) is considered to be zero at all temperatures.(ii) e.m.f. of the cell Pt(s)/H2(g, 1 bar )/H+ (aq, 1 M) || Zn2+ (aq,1M) / Z n is – 0.76. This negative value indicates that Zn2+ ion reduces less easily then H+ ions.(iii) Copper does not dissolve in HCl but dissolves in HNO3 as in nitric acid it gets oxidised by nitrate ions.(iv) Inert metals like Pt or Au are used in certain electrodes i.e., these metals does not participate in reaction but provide surface for oxidation and reduction reactions. (v) Fluorine has the highest electrode potential thereby making it the strongest oxidising agent whereas lithium with lowest electrode potential is the weakest oxidising and strongest reducing agent.Which of the following are the correct statements above?

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Which one of the following is the strongest oxidising agent a)BrO3^-/Br^2+, E^o=+1.50 b)Fe^3+/Fe^2+, E^o=+0.76 c)MnO4^-/Mn^2+,E^o=+1.52 d)Cr2O7^2-/Cr^3+,E^o=+1.33
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Which one of the following is the strongest oxidising agent a)BrO3^-/Br^2+, E^o=+1.50 b)Fe^3+/Fe^2+, E^o=+0.76 c)MnO4^-/Mn^2+,E^o=+1.52 d)Cr2O7^2-/Cr^3+,E^o=+1.33 for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Which one of the following is the strongest oxidising agent a)BrO3^-/Br^2+, E^o=+1.50 b)Fe^3+/Fe^2+, E^o=+0.76 c)MnO4^-/Mn^2+,E^o=+1.52 d)Cr2O7^2-/Cr^3+,E^o=+1.33 covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which one of the following is the strongest oxidising agent a)BrO3^-/Br^2+, E^o=+1.50 b)Fe^3+/Fe^2+, E^o=+0.76 c)MnO4^-/Mn^2+,E^o=+1.52 d)Cr2O7^2-/Cr^3+,E^o=+1.33.
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