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Two particles of mass 5kg and 10 kg respectively are attached to the two ends of a rigid rod of length 1m with negligible mass. The centre of mass of the system from the 5kg particle is nearly at a distance of:
- a)67 cm
- b)80 cm
- c)33 cm
- d)50 cm
Correct answer is option 'A'. Can you explain this answer?
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Two particles of mass 5kg and 10 kg respectively are attached to the t...
= 0.67 m = 67 cm
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Two particles of mass 5kg and 10 kg respectively are attached to the t...
To find the position of the center of mass of the system, we can use the principle of symmetry. Since the rigid rod is of negligible mass and the two particles have different masses, the center of mass will lie closer to the heavier particle.
Let's assume that the center of mass is at a distance x from the 5 kg particle.
Calculating the center of mass:
We can calculate the center of mass using the formula:
x_cm = (m1 * x1 + m2 * x2) / (m1 + m2)
where m1 and m2 are the masses of the particles, and x1 and x2 are the distances of the particles from the center of mass.
In this case, m1 = 5 kg, m2 = 10 kg, x1 = x (distance from the 5 kg particle), and x2 = 1 - x (distance from the 10 kg particle).
Substituting these values into the formula, we get:
x_cm = (5 * x + 10 * (1 - x)) / (5 + 10)
= (5x + 10 - 10x) / 15
= (10 - 5x) / 15
Since the center of mass is closer to the 10 kg particle, we know that x_cm < 1="" (the="" length="" of="" the="" />
Simplifying the equation further, we have:
10 - 5x < />
-5x < />
x > -1
Since x must be greater than -1 and less than 1, we can conclude that the center of mass is approximately 0.67 m or 67 cm from the 5 kg particle.
Therefore, the correct answer is option A) 67 cm.
Let's assume that the center of mass is at a distance x from the 5 kg particle.
Calculating the center of mass:
We can calculate the center of mass using the formula:
x_cm = (m1 * x1 + m2 * x2) / (m1 + m2)
where m1 and m2 are the masses of the particles, and x1 and x2 are the distances of the particles from the center of mass.
In this case, m1 = 5 kg, m2 = 10 kg, x1 = x (distance from the 5 kg particle), and x2 = 1 - x (distance from the 10 kg particle).
Substituting these values into the formula, we get:
x_cm = (5 * x + 10 * (1 - x)) / (5 + 10)
= (5x + 10 - 10x) / 15
= (10 - 5x) / 15
Since the center of mass is closer to the 10 kg particle, we know that x_cm < 1="" (the="" length="" of="" the="" />
Simplifying the equation further, we have:
10 - 5x < />
-5x < />
x > -1
Since x must be greater than -1 and less than 1, we can conclude that the center of mass is approximately 0.67 m or 67 cm from the 5 kg particle.
Therefore, the correct answer is option A) 67 cm.
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Two particles of mass 5kg and 10 kg respectively are attached to the two ends of a rigid rod of length 1m with negligible mass. The centre of mass of the system from the 5kg particle is nearly at a distance of:a)67 cmb)80 cmc)33 cmd)50 cmCorrect answer is option 'A'. Can you explain this answer?
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Two particles of mass 5kg and 10 kg respectively are attached to the two ends of a rigid rod of length 1m with negligible mass. The centre of mass of the system from the 5kg particle is nearly at a distance of:a)67 cmb)80 cmc)33 cmd)50 cmCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two particles of mass 5kg and 10 kg respectively are attached to the two ends of a rigid rod of length 1m with negligible mass. The centre of mass of the system from the 5kg particle is nearly at a distance of:a)67 cmb)80 cmc)33 cmd)50 cmCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two particles of mass 5kg and 10 kg respectively are attached to the two ends of a rigid rod of length 1m with negligible mass. The centre of mass of the system from the 5kg particle is nearly at a distance of:a)67 cmb)80 cmc)33 cmd)50 cmCorrect answer is option 'A'. Can you explain this answer?.
Two particles of mass 5kg and 10 kg respectively are attached to the two ends of a rigid rod of length 1m with negligible mass. The centre of mass of the system from the 5kg particle is nearly at a distance of:a)67 cmb)80 cmc)33 cmd)50 cmCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two particles of mass 5kg and 10 kg respectively are attached to the two ends of a rigid rod of length 1m with negligible mass. The centre of mass of the system from the 5kg particle is nearly at a distance of:a)67 cmb)80 cmc)33 cmd)50 cmCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two particles of mass 5kg and 10 kg respectively are attached to the two ends of a rigid rod of length 1m with negligible mass. The centre of mass of the system from the 5kg particle is nearly at a distance of:a)67 cmb)80 cmc)33 cmd)50 cmCorrect answer is option 'A'. Can you explain this answer?.
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