1 ml of H2O2 solution gives 10 ml of O2 at NTP it is _____ vol. H2O2
Introduction:
In this question, we are given that 1 ml of H2O2 solution gives 10 ml of O2 at NTP (Normal Temperature and Pressure). We are asked to determine the volume of H2O2 in the solution.
Explanation:
To solve this problem, we need to use the concept of stoichiometry, which is the relationship between the amounts of reactants and products in a chemical reaction.
Step 1: Balanced Chemical Equation:
First, let's write the balanced chemical equation for the decomposition of hydrogen peroxide (H2O2) into water (H2O) and oxygen gas (O2):
2H2O2 → 2H2O + O2
Step 2: Stoichiometry Calculation:
According to the balanced equation, 2 moles of hydrogen peroxide (H2O2) produce 1 mole of oxygen gas (O2). Therefore, the stoichiometric ratio is 2:1.
Step 3: Calculation of Moles:
We can use the stoichiometric ratio to calculate the number of moles of H2O2 in the solution. Since we know that 1 ml of H2O2 solution gives 10 ml of O2, we can convert the volume of O2 to moles using the ideal gas law:
PV = nRT
At NTP, the pressure (P) is 1 atm, the volume (V) is 10 ml (converted to liters), the number of moles (n) is what we need to calculate, the gas constant (R) is 0.0821 L·atm/mol·K, and the temperature (T) is 273 K.
Using the ideal gas law equation, we can calculate the number of moles of O2 gas:
n = PV / RT = (1 atm * 10 mL) / (0.0821 L·atm/mol·K * 273 K)
Step 4: Calculation of Volume of H2O2:
Now that we have the number of moles of O2 gas, we can use the stoichiometric ratio to determine the number of moles of H2O2. Since the stoichiometric ratio is 2:1, we divide the number of moles of O2 gas by 2.
Step 5: Conversion to Volume:
Finally, we can convert the number of moles of H2O2 to volume using the molar volume of a gas at NTP, which is 22.4 L/mol. We multiply the number of moles of H2O2 by the molar volume to get the volume in liters.
Step 6: Final Answer:
The final answer is the volume of H2O2 in liters.
Conclusion:
To summarize, we can determine the volume of H2O2 in the solution by using stoichiometry and the ideal gas law. By converting the volume of O2 gas to moles, using the stoichiometric ratio, and then converting the number of moles to volume, we can find the volume of H2O2 in the solution.
1 ml of H2O2 solution gives 10 ml of O2 at NTP it is _____ vol. H2O2
22.4l
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