A particle having initial velocity u moves with constant acceleration ...
A particle having initial velocity u moves with constant acceleration ...
Displacement of a Particle with Constant Acceleration
Part (a)
To find the displacement of the particle in the last 1 second, we need to use the formula:
s = ut + 1/2at^2
where s is the displacement, u is the initial velocity, a is the acceleration, and t is the time taken.
We know that the particle has been moving with constant acceleration for time t, so the displacement of the particle in the last 1 second can be found by subtracting the displacement of the particle in the first t-1 seconds from the total displacement in time t.
Thus, the displacement of the particle in the last 1 second is given by:
s1 = (u(t) - u(t-1)) + 1/2a(1)^2
where u(t) is the velocity of the particle at time t, and u(t-1) is the velocity of the particle at time t-1.
Part (b)
Given, u = 5 m/s, a = 2 m/s², and t = 10 seconds.
Using the formula s = ut + 1/2at^2, we can find the displacement of the particle in time t:
s = ut + 1/2at^2
s = (5)(10) + 1/2(2)(10)^2
s = 50 + 100
s = 150 m
To find the displacement of the particle in the last 1 second, we can use the formula derived in part (a):
s1 = (u(t) - u(t-1)) + 1/2a(1)^2
s1 = (5(10) - 5(9)) + 1/2(2)(1)^2
s1 = 5 + 1
s1 = 6 m
Therefore, the displacement of the particle in the last 1 second is 6 m.
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