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A taxi leaves the station X for station Y every 10 minutes. Simultaneously, a taxi leaves the station Y also for station X every 10 minutes. The taxi move at the same constant speed and go from X to Y or vice versa in 2 hours. how many texts coming from other side will each taxi meet enroute from Y to X
Verified Answer
A taxi leaves the station X for station Y every 10 minutes. Simultaneo...
When the taxi is just about to leave there will be taxis coming from the opposite side;Our taxi will surely meet those taxis. So, no. of taxis which will be in the path are:[(total time each taxi takes to reach destination)/(total time after which each taxi leaves the station)] + 1In this case it is:120/10 + 1= 12+1=13(+1 as we need to take both the last and the first taxi).So, we have total of 13 taxis on the path out of which we will subtract 1 as we are not considering the taxi meeting station Y.Now, we need to calculate the no. of taxis which leave after our taxi leaves;Those will be again:[(total time each taxi takes to reach destination)/(total time after which each taxi leaves the station)] +1in our case it is120/10 + 1= 12+1=13(+1 as we need to take both the last and the first taxi).Now, we will subtract 2 as we have counted the taxi which will leave station X when our taxi leaves station Y twice and also as we are not considering the taxi meeting station X.So, now we have a total of 12+11=23 taxis coming from other side which each taxi will meet enroute from Y to X.
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Most Upvoted Answer
A taxi leaves the station X for station Y every 10 minutes. Simultaneo...
2hr=120min.within this time both taxi will leave the station for 12 times nd come back for 11 times.as both taxis are moving simultaneously they will cross each other for 23 times.
Community Answer
A taxi leaves the station X for station Y every 10 minutes. Simultaneo...
Introduction:

In this scenario, we have two taxis traveling between two stations, X and Y. They leave their respective stations every 10 minutes and travel at the same constant speed. The distance between the two stations is covered by each taxi in 2 hours. We need to determine how many taxis coming from the other side each taxi will meet en route from Y to X.

Analysis:

To solve this problem, let's consider the time it takes for a taxi to travel between the two stations. Each taxi takes 2 hours to complete the journey, which is equivalent to 120 minutes.

Calculating the number of taxis:

1. First, we need to find the number of taxis that leave each station in 120 minutes. Since a taxi leaves every 10 minutes, we can divide the total time (120 minutes) by the time interval between each taxi departure (10 minutes).

Number of taxis leaving from station X = 120 minutes / 10 minutes = 12 taxis
Number of taxis leaving from station Y = 120 minutes / 10 minutes = 12 taxis

Therefore, there are 12 taxis leaving from each station in a span of 120 minutes.

2. Now, let's consider the scenario where a taxi leaves from station X. For this taxi to meet a taxi coming from the other side (station Y) while traveling from Y to X, it needs to encounter the taxis that left from station Y during the 120-minute journey.

a. The first taxi leaving from station Y will take 10 minutes to reach the halfway point between the two stations. At this point, the taxi from station X will have traveled for 10 minutes.
b. The second taxi leaving from station Y will take 20 minutes to reach the halfway point, and the taxi from station X will have traveled for 20 minutes.
c. This pattern continues, and for each taxi leaving from station Y, the taxi from station X will have traveled an additional 10 minutes.

Therefore, the number of taxis coming from the other side (station Y) that each taxi from station X will meet en route from Y to X is equal to the number of taxis leaving from station Y in a span of 120 minutes, which is 12 taxis.

Conclusion:

Each taxi leaving from station X will meet 12 taxis coming from the other side (station Y) while traveling from Y to X. This is because the taxis leave at the same constant speed and every 10 minutes, and the total journey time is 2 hours.
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Read the passage given below and answer the following questions:Nucleophilic substitution reaction of haloalkane can be conducted according to both SN1 and SN2 mechanisms. However, which mechanism it is based on is related to such factors as the structure of haloalkane, and properties of leaving group, nucleophilic reagent and solvent. Influences of halogen: No matter which mechanism the nucleophilic substitution reaction is based on, the leaving group always leave the central carbon atom with electron pair. This is just the opposite of the situation that nucleophilic reagent attacks the central carbon atom with electron pair. Therefore, the weaker the alkalinity of leaving group is , the more stable the anion formed is and it will be more easier for the leaving group to leave the central carbon atom; that is to say, the reactant is more easier to be substituted. The alkalinity order of halogen ion is I− < Br− < Cl− < F− and the order of their leaving tendency should be I− > Br− > Cl− > F−. Therefore, in four halides with the same alkyl and different halogens, the order of substitution reaction rate is RI > RBr > RCl > RF. In addition, if the leaving group is very easy to leave, many carbocation intermediates are generated in the reaction and the reaction is based on SN1 mechanism. If the leaving group is not easy to leave, the reaction is based on SN2 mechanism. Influences of solvent polarity: In SN1 reaction, the polarity of the system increases from the reactant to the transition state, because polar solvent has a greater stabilizing effect on the transition state than the reactant, thereby reduce activation energy and accelerate the reaction. In SN2 reaction, the polarity of the system generally does not change from the reactant to the transition state and only charge dispersion occurs. At this time, polar solvent has a great stabilizing effect on Nu than the transition state, thereby increasing activation energy and slow down the reaction rate. For example, the decomposition rate (SN1) of tertiary chlorobutane in 25° water (dielectric constant 79) is 300000 times faster than in ethanol (dielectric constant 24). The reaction rate (SN2) of 2-bromopropane and NaOH in ethanol containing 40% water is twice slower than in absolute ethanol. In a word, the level of solvent polarity has influence on both SN1 and SN2 reactions, but with different results. Generally speaking, weak polar solvent is favorable for SN2 reaction, while strong polar solvent is favorable for SN1 reaction, because only under the action of polar solvent can halogenated hydrocarbon dissociate into carbocation and halogen ion and solvents with a strong polarity is favorable for solvation of carbocation, increasing its stability. Generally speaking, the substitution reaction of tertiary haloalkane is based on SN1 mechanism in solvents with a strong polarity (for example, ethanol containing water).Q. SN1 reaction will be fastest in which of the following solvents?

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A taxi leaves the station X for station Y every 10 minutes. Simultaneously, a taxi leaves the station Y also for station X every 10 minutes. The taxi move at the same constant speed and go from X to Y or vice versa in 2 hours. how many texts coming from other side will each taxi meet enroute from Y to X
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A taxi leaves the station X for station Y every 10 minutes. Simultaneously, a taxi leaves the station Y also for station X every 10 minutes. The taxi move at the same constant speed and go from X to Y or vice versa in 2 hours. how many texts coming from other side will each taxi meet enroute from Y to X for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A taxi leaves the station X for station Y every 10 minutes. Simultaneously, a taxi leaves the station Y also for station X every 10 minutes. The taxi move at the same constant speed and go from X to Y or vice versa in 2 hours. how many texts coming from other side will each taxi meet enroute from Y to X covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A taxi leaves the station X for station Y every 10 minutes. Simultaneously, a taxi leaves the station Y also for station X every 10 minutes. The taxi move at the same constant speed and go from X to Y or vice versa in 2 hours. how many texts coming from other side will each taxi meet enroute from Y to X.
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