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The voltage phapor of a circuit is 10∠15° V and the current phasor is 2∠- 45° A. The active and the reactive powers in the circuit are
  • a)
    10 W and 17.32 VAr
  • b)
    20√2 W and 10√2 VAr
  • c)
    200 W and 60 VAr
  • d)
    5 W and 8.66 VAr
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The voltage phapor of a circuit is 10∠15° V and the current ph...
S = VI* = (10∠15°) (2∠ - 45°)*
= 20∠15 + 45° = 20∠60°
= 20 (cos 60° + j sin 60°)

= (10 + j10√3) = (10 + j17.32)
= P+ jQ
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Most Upvoted Answer
The voltage phapor of a circuit is 10∠15° V and the current ph...
Volts. Can you provide more information or context for your question?
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