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An observer 1.5 m tall is 28.5 m away from.a chimney. The angle of elevation of the top of the chimney from her eyes is 45°. The height of the chimney is :
- a)30 m
- b)27 m
- c)28.5 m
- d)None of these.
Correct answer is option 'A'. Can you explain this answer?
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An observer 1.5 m tall is 28.5 m away from.a chimney. The angle of ele...
°. Find the height of the chimney.
Let's call the height of the chimney "h". We can use trigonometry to solve for "h".
First, let's draw a diagram:
```
A
/|
h / |
/ |
/ | 1.5 m
/θ |
-----
28.5 m
```
In this diagram, "h" is the height of the chimney, "A" is the top of the chimney, "θ" is the angle of elevation, and the vertical line represents the observer's height of 1.5 m.
From the diagram, we can see that:
tan(θ) = opposite/adjacent
where "opposite" is the height of the chimney and "adjacent" is the distance from the observer to the base of the chimney. We can plug in the values we know:
tan(45°) = h/28.5
Solving for "h", we get:
h = 28.5 * tan(45°)
h = 28.5 * 1
h = 28.5
Therefore, the height of the chimney is 28.5 meters.
Let's call the height of the chimney "h". We can use trigonometry to solve for "h".
First, let's draw a diagram:
```
A
/|
h / |
/ |
/ | 1.5 m
/θ |
-----
28.5 m
```
In this diagram, "h" is the height of the chimney, "A" is the top of the chimney, "θ" is the angle of elevation, and the vertical line represents the observer's height of 1.5 m.
From the diagram, we can see that:
tan(θ) = opposite/adjacent
where "opposite" is the height of the chimney and "adjacent" is the distance from the observer to the base of the chimney. We can plug in the values we know:
tan(45°) = h/28.5
Solving for "h", we get:
h = 28.5 * tan(45°)
h = 28.5 * 1
h = 28.5
Therefore, the height of the chimney is 28.5 meters.
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An observer 1.5 m tall is 28.5 m away from.a chimney. The angle of elevation of the top of thechimney from her eyes is 45°. The height of the chimney is :a)30 mb)27 mc)28.5 md)None of these.Correct answer is option 'A'. Can you explain this answer?
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