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The vapour density of a volatile chloride of a metal is 59.5 and the equivalent mass of the metal is 24 . What will be the atomic mass of the element ?
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The vapour density of a volatile chloride of a metal is 59.5 and the e...
Calculating Atomic Mass of the Element
There are a few steps to follow in order to calculate the atomic mass of the element based on the given information:
1. Calculate the molecular weight of the volatile chloride of the metal:
- The vapour density of the volatile chloride is 59.5, which means that its molecular weight is 59.5 times the weight of hydrogen (since hydrogen is the reference element for vapour density).
- The weight of hydrogen is 1 atomic mass unit (amu), so the molecular weight of the volatile chloride is 59.5 amu.
2. Determine the formula of the volatile chloride:
- The equivalent mass of the metal is 24, which means that 1 mole of the metal combines with 2 moles of chlorine (since chlorine has an equivalent weight of 35.5).
- Therefore, the formula of the volatile chloride is MCl2 (where M is the metal).
3. Calculate the atomic mass of the metal:
- The molecular weight of the volatile chloride (59.5 amu) is equal to the sum of the atomic weight of the metal (M) and twice the atomic weight of chlorine (Cl):
- 59.5 = M + 2(35.5)
- 59.5 = M + 71
- M = -11.5
- The negative value for M is not possible, so we must conclude that there is an error in the given information.
Conclusion
Based on the given information, it is not possible to calculate the atomic mass of the element. The negative value obtained in Step 3 indicates that there is an error either in the vapour density or the equivalent mass of the metal.
There are a few steps to follow in order to calculate the atomic mass of the element based on the given information:
1. Calculate the molecular weight of the volatile chloride of the metal:
- The vapour density of the volatile chloride is 59.5, which means that its molecular weight is 59.5 times the weight of hydrogen (since hydrogen is the reference element for vapour density).
- The weight of hydrogen is 1 atomic mass unit (amu), so the molecular weight of the volatile chloride is 59.5 amu.
2. Determine the formula of the volatile chloride:
- The equivalent mass of the metal is 24, which means that 1 mole of the metal combines with 2 moles of chlorine (since chlorine has an equivalent weight of 35.5).
- Therefore, the formula of the volatile chloride is MCl2 (where M is the metal).
3. Calculate the atomic mass of the metal:
- The molecular weight of the volatile chloride (59.5 amu) is equal to the sum of the atomic weight of the metal (M) and twice the atomic weight of chlorine (Cl):
- 59.5 = M + 2(35.5)
- 59.5 = M + 71
- M = -11.5
- The negative value for M is not possible, so we must conclude that there is an error in the given information.
Conclusion
Based on the given information, it is not possible to calculate the atomic mass of the element. The negative value obtained in Step 3 indicates that there is an error either in the vapour density or the equivalent mass of the metal.
Community Answer
The vapour density of a volatile chloride of a metal is 59.5 and the e...
By using formula 2 * VD/ Equ weight + molar mass of chloride
we will get ans
we will get ans
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The vapour density of a volatile chloride of a metal is 59.5 and the equivalent mass of the metal is 24 . What will be the atomic mass of the element ?
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The vapour density of a volatile chloride of a metal is 59.5 and the equivalent mass of the metal is 24 . What will be the atomic mass of the element ? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The vapour density of a volatile chloride of a metal is 59.5 and the equivalent mass of the metal is 24 . What will be the atomic mass of the element ? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The vapour density of a volatile chloride of a metal is 59.5 and the equivalent mass of the metal is 24 . What will be the atomic mass of the element ?.
The vapour density of a volatile chloride of a metal is 59.5 and the equivalent mass of the metal is 24 . What will be the atomic mass of the element ? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The vapour density of a volatile chloride of a metal is 59.5 and the equivalent mass of the metal is 24 . What will be the atomic mass of the element ? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The vapour density of a volatile chloride of a metal is 59.5 and the equivalent mass of the metal is 24 . What will be the atomic mass of the element ?.
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