Answer:

Explanation:
According to Avogadro's law, equal volumes of all gases at the same temperature and pressure contain the same number of molecules, i.e., 1 mole of any gas occupies 22.4 L at STP (Standard Temperature and Pressure).

Given, Vd = 11.2 L
We know, 1 mole of gas occupies 22.4 L at STP
So, the number of moles of gas present can be calculated as follows:

n = Vd / 22.4
n = 11.2 / 22.4
n = 0.5 moles

We are also given the mass of the gas, which is 2.4 g. Using the molar mass of the gas, we can calculate the number of moles of gas as follows:

molar mass = mass / number of moles
number of moles = mass / molar mass

Let's assume the molar mass of the gas is M.

number of moles = 2.4 / M

We can now equate the two expressions for the number of moles of gas:

0.5 = 2.4 / M

M = 4.8 g/mol

Now, we can use the molar volume of the gas at STP to calculate the volume occupied by 2.4 g of the gas.

Volume occupied by 1 mole of gas at STP is 22.4 L
Volume occupied by 4.8 g of the gas at STP can be calculated as follows:

number of moles = mass / molar mass
number of moles = 4.8 / 4.8
number of moles = 1 mole

So, the volume occupied by 4.8 g of the gas at STP is 22.4 L.

Volume occupied by 2.4 g of the gas at STP can be calculated as follows:

Volume occupied by 4.8 g of gas = 22.4 L
Volume occupied by 1 g of gas = 22.4 / 4.8 = 4.67 L
Volume occupied by 2.4 g of gas = 4.67 x 2.4 = 11.2 L

Therefore, the volume occupied by 2.4 g of the gas at STP is 11.2 L.

Answer: Option 1) 11.2L