Had moderately low pressure, if RT = 2√a.P, then the volume occupied by 1 mole of real gas is (1) 2RT/P (2) RT / 2P (3) 2P / RT (4) 2R / PT?

Question

Answer

Explanation:

Given:

Pressure, P = moderately low

Relation, RT = 2√a.P

Volume occupied by 1 mole of real gas = ?

Formula:

For 1 mole of real gas, PV = RT

where,

P = pressure

V = volume

R = gas constant

T = temperature

Solution:

Given relation, RT = 2√a.P

Dividing both sides by P, we get:

RT/P = 2√a

Substituting RT/P as 2√a, we get:

V = 2√a.RT/P

Dividing both sides by RT/P, we get:

V = 2R/PT

Therefore, the volume occupied by 1 mole of real gas is 2R/PT.