Subsidiary Alliance of Wellesley was a policy implemented by Lord Wellesley, the Governor-General of India from 1798 to 1805, to control and expand British influence in India. Under this policy, several Indian states were brought under the protection of the British East India Company in exchange for a subsidy. The question asks to arrange the subsidized states chronologically under the Subsidiary Alliance of Wellesley.

1. Hyderabad
2. Peshwa
3. Jaipur
4. Bharatpur

The correct arrangement is: 1-2-4-3

Explanation:

1. Hyderabad:
Hyderabad was the first state to come under the Subsidiary Alliance of Wellesley in 1798. The Nizam of Hyderabad, a powerful ruler in South India, entered into a subsidiary alliance with the British East India Company. According to the alliance, the Nizam had to maintain a British subsidiary force in his territory and pay a subsidy to the British.

2. Peshwa:
The Peshwa or the Maratha Empire was the second state to enter into the Subsidiary Alliance. In 1802, the Peshwa Baji Rao II signed the treaty of Bassein with the British East India Company, which made Pune the capital of the Maratha Empire. The Peshwa had to accept a British subsidiary force, cede territories, and pay a subsidy to the British.

3. Jaipur:
Jaipur, the capital of the princely state of Rajasthan, came under the Subsidiary Alliance in 1803. The Maharaja of Jaipur, Bhim Singh, signed a treaty with the British East India Company, which required him to accept a British subsidiary force, cede territories, and pay a subsidy.

4. Bharatpur:
Bharatpur, another princely state in Rajasthan, entered into the Subsidiary Alliance in 1803. The Jat ruler of Bharatpur, Maharaja Ranjit Singh, agreed to the terms of the alliance, which included accepting a British subsidiary force, ceding territories, and paying a subsidy.

Therefore, the correct chronological arrangement of the subsidized states under the Subsidiary Alliance of Wellesley is 1-2-4-3, with Hyderabad being the first, followed by Peshwa, Bharatpur, and Jaipur.