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CH3COOH C2H5OH gives CH3COOC2H5 H2O In the above reaction one mole of each acetic acid and alcohol are heated in presence of little concentrated H2SO4. On equilibrium being achieved a)1 mole of ethyl acetate is formed b)2 mole of ethyl acetate are formed c)1/2 mole of ethyl acetate is formed d)2/3 mole of ethyl acetate is formed?
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CH3COOH C2H5OH gives CH3COOC2H5 H2O In the above reaction one mole of ...
Answer:
To determine the amount of ethyl acetate formed in the reaction between acetic acid (CH3COOH) and ethanol (C2H5OH), we need to consider the stoichiometry of the reaction and the principle of equilibrium.
The balanced equation for the reaction is:
CH3COOH + C2H5OH → CH3COOC2H5 + H2O
Stoichiometry of the reaction:
From the balanced equation, we can see that 1 mole of acetic acid reacts with 1 mole of ethanol to produce 1 mole of ethyl acetate and 1 mole of water.
Principle of equilibrium:
When a reaction reaches equilibrium, the rate of the forward reaction is equal to the rate of the reverse reaction. At equilibrium, the concentrations of all the reactants and products remain constant.
In this case, the reaction is reversible, and the formation of ethyl acetate can be considered as the forward reaction. The reverse reaction is the hydrolysis of ethyl acetate to regenerate acetic acid and ethanol.
Explanation:
Since the reaction is reversible, the amount of ethyl acetate formed at equilibrium depends on the initial amounts of acetic acid and ethanol.
If 1 mole of acetic acid and 1 mole of ethanol are reacted, the reaction will proceed until equilibrium is reached. At equilibrium, 1 mole of ethyl acetate and 1 mole of water will be formed.
Therefore, the correct answer is (a) 1 mole of ethyl acetate is formed.
The presence of concentrated sulfuric acid acts as a catalyst in this reaction. It helps in the formation of the ester by protonating the carbonyl oxygen of the acetic acid, making it more reactive towards nucleophilic attack by the ethanol. The sulfuric acid also helps in the removal of water, driving the equilibrium towards the formation of ethyl acetate.
Overall, the reaction between acetic acid and ethanol is an example of an esterification reaction, which is a type of condensation reaction.
To determine the amount of ethyl acetate formed in the reaction between acetic acid (CH3COOH) and ethanol (C2H5OH), we need to consider the stoichiometry of the reaction and the principle of equilibrium.
The balanced equation for the reaction is:
CH3COOH + C2H5OH → CH3COOC2H5 + H2O
Stoichiometry of the reaction:
From the balanced equation, we can see that 1 mole of acetic acid reacts with 1 mole of ethanol to produce 1 mole of ethyl acetate and 1 mole of water.
Principle of equilibrium:
When a reaction reaches equilibrium, the rate of the forward reaction is equal to the rate of the reverse reaction. At equilibrium, the concentrations of all the reactants and products remain constant.
In this case, the reaction is reversible, and the formation of ethyl acetate can be considered as the forward reaction. The reverse reaction is the hydrolysis of ethyl acetate to regenerate acetic acid and ethanol.
Explanation:
Since the reaction is reversible, the amount of ethyl acetate formed at equilibrium depends on the initial amounts of acetic acid and ethanol.
If 1 mole of acetic acid and 1 mole of ethanol are reacted, the reaction will proceed until equilibrium is reached. At equilibrium, 1 mole of ethyl acetate and 1 mole of water will be formed.
Therefore, the correct answer is (a) 1 mole of ethyl acetate is formed.
The presence of concentrated sulfuric acid acts as a catalyst in this reaction. It helps in the formation of the ester by protonating the carbonyl oxygen of the acetic acid, making it more reactive towards nucleophilic attack by the ethanol. The sulfuric acid also helps in the removal of water, driving the equilibrium towards the formation of ethyl acetate.
Overall, the reaction between acetic acid and ethanol is an example of an esterification reaction, which is a type of condensation reaction.
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CH3COOH C2H5OH gives CH3COOC2H5 H2O In the above reaction one mole of ...
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CH3COOH C2H5OH gives CH3COOC2H5 H2O In the above reaction one mole of each acetic acid and alcohol are heated in presence of little concentrated H2SO4. On equilibrium being achieved a)1 mole of ethyl acetate is formed b)2 mole of ethyl acetate are formed c)1/2 mole of ethyl acetate is formed d)2/3 mole of ethyl acetate is formed?
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CH3COOH C2H5OH gives CH3COOC2H5 H2O In the above reaction one mole of each acetic acid and alcohol are heated in presence of little concentrated H2SO4. On equilibrium being achieved a)1 mole of ethyl acetate is formed b)2 mole of ethyl acetate are formed c)1/2 mole of ethyl acetate is formed d)2/3 mole of ethyl acetate is formed? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about CH3COOH C2H5OH gives CH3COOC2H5 H2O In the above reaction one mole of each acetic acid and alcohol are heated in presence of little concentrated H2SO4. On equilibrium being achieved a)1 mole of ethyl acetate is formed b)2 mole of ethyl acetate are formed c)1/2 mole of ethyl acetate is formed d)2/3 mole of ethyl acetate is formed? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for CH3COOH C2H5OH gives CH3COOC2H5 H2O In the above reaction one mole of each acetic acid and alcohol are heated in presence of little concentrated H2SO4. On equilibrium being achieved a)1 mole of ethyl acetate is formed b)2 mole of ethyl acetate are formed c)1/2 mole of ethyl acetate is formed d)2/3 mole of ethyl acetate is formed?.
CH3COOH C2H5OH gives CH3COOC2H5 H2O In the above reaction one mole of each acetic acid and alcohol are heated in presence of little concentrated H2SO4. On equilibrium being achieved a)1 mole of ethyl acetate is formed b)2 mole of ethyl acetate are formed c)1/2 mole of ethyl acetate is formed d)2/3 mole of ethyl acetate is formed? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about CH3COOH C2H5OH gives CH3COOC2H5 H2O In the above reaction one mole of each acetic acid and alcohol are heated in presence of little concentrated H2SO4. On equilibrium being achieved a)1 mole of ethyl acetate is formed b)2 mole of ethyl acetate are formed c)1/2 mole of ethyl acetate is formed d)2/3 mole of ethyl acetate is formed? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for CH3COOH C2H5OH gives CH3COOC2H5 H2O In the above reaction one mole of each acetic acid and alcohol are heated in presence of little concentrated H2SO4. On equilibrium being achieved a)1 mole of ethyl acetate is formed b)2 mole of ethyl acetate are formed c)1/2 mole of ethyl acetate is formed d)2/3 mole of ethyl acetate is formed?.
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CH3COOH C2H5OH gives CH3COOC2H5 H2O In the above reaction one mole of each acetic acid and alcohol are heated in presence of little concentrated H2SO4. On equilibrium being achieved a)1 mole of ethyl acetate is formed b)2 mole of ethyl acetate are formed c)1/2 mole of ethyl acetate is formed d)2/3 mole of ethyl acetate is formed?, a detailed solution for CH3COOH C2H5OH gives CH3COOC2H5 H2O In the above reaction one mole of each acetic acid and alcohol are heated in presence of little concentrated H2SO4. On equilibrium being achieved a)1 mole of ethyl acetate is formed b)2 mole of ethyl acetate are formed c)1/2 mole of ethyl acetate is formed d)2/3 mole of ethyl acetate is formed? has been provided alongside types of CH3COOH C2H5OH gives CH3COOC2H5 H2O In the above reaction one mole of each acetic acid and alcohol are heated in presence of little concentrated H2SO4. On equilibrium being achieved a)1 mole of ethyl acetate is formed b)2 mole of ethyl acetate are formed c)1/2 mole of ethyl acetate is formed d)2/3 mole of ethyl acetate is formed? theory, EduRev gives you an
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