GATE Exam > GATE Questions > A tractor PTO operated 4-disc rotary mower is...
Start Learning for Free
A tractor PTO operated 4-disc rotary mower is harvesting with a forward speed of 3.5 km h-1. The cutting circle diameter and rpm of each disc are 60 cm and 1400, respectively. The peak cutting force experienced by each rotary disc is 110 N. The peak overall motion resistance is found to be 3.6 kN. If the overall power conversion efficiency of the tractor is 82%, required peak engine brake power in kW will be __________
Correct answer is between '27.0,28.5'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
A tractor PTO operated 4-disc rotary mower is harvesting with a forwar...
To calculate the required peak engine brake power, we need to consider the cutting power required by the mower and the overall power conversion efficiency of the tractor.
1. Calculate the cutting power:
The cutting power can be calculated using the formula:
Cutting power = Peak cutting force x Cutting speed
The cutting speed can be calculated by converting the forward speed of the tractor into meters per second and multiplying it by the circumference of the cutting circle:
Cutting speed = (Forward speed x 1000) / (60 x 60) (converted to m/s)
Cutting power = 110 N x Cutting speed
2. Calculate the overall power consumption:
The overall power consumption of the tractor can be calculated by adding the power required for cutting to the power required to overcome the motion resistance:
Overall power consumption = Cutting power + Peak overall motion resistance
3. Calculate the required peak engine brake power:
The required peak engine brake power can be calculated by dividing the overall power consumption by the overall power conversion efficiency of the tractor:
Required peak engine brake power = Overall power consumption / Overall power conversion efficiency
Now let's plug in the given values and calculate the required peak engine brake power:
Forward speed = 3.5 km/h = 3.5 x 1000 / 60 x 60 = 0.972 m/s
Cutting speed = (0.972 x 1000) / (60 x 60) = 0.27 m/s
Cutting power = 110 N x 0.27 m/s = 29.7 W
Peak overall motion resistance = 3.6 kN = 3.6 x 1000 N = 3600 N
Overall power consumption = 29.7 W + 3600 N x 0.27 m/s = 29.7 W + 972 W = 1001.7 W
Overall power conversion efficiency = 82% = 0.82
Required peak engine brake power = 1001.7 W / 0.82 = 1221.83 W = 1.22183 kW
Therefore, the required peak engine brake power is between 27.0 kW and 28.5 kW.
1. Calculate the cutting power:
The cutting power can be calculated using the formula:
Cutting power = Peak cutting force x Cutting speed
The cutting speed can be calculated by converting the forward speed of the tractor into meters per second and multiplying it by the circumference of the cutting circle:
Cutting speed = (Forward speed x 1000) / (60 x 60) (converted to m/s)
Cutting power = 110 N x Cutting speed
2. Calculate the overall power consumption:
The overall power consumption of the tractor can be calculated by adding the power required for cutting to the power required to overcome the motion resistance:
Overall power consumption = Cutting power + Peak overall motion resistance
3. Calculate the required peak engine brake power:
The required peak engine brake power can be calculated by dividing the overall power consumption by the overall power conversion efficiency of the tractor:
Required peak engine brake power = Overall power consumption / Overall power conversion efficiency
Now let's plug in the given values and calculate the required peak engine brake power:
Forward speed = 3.5 km/h = 3.5 x 1000 / 60 x 60 = 0.972 m/s
Cutting speed = (0.972 x 1000) / (60 x 60) = 0.27 m/s
Cutting power = 110 N x 0.27 m/s = 29.7 W
Peak overall motion resistance = 3.6 kN = 3.6 x 1000 N = 3600 N
Overall power consumption = 29.7 W + 3600 N x 0.27 m/s = 29.7 W + 972 W = 1001.7 W
Overall power conversion efficiency = 82% = 0.82
Required peak engine brake power = 1001.7 W / 0.82 = 1221.83 W = 1.22183 kW
Therefore, the required peak engine brake power is between 27.0 kW and 28.5 kW.
|
Explore Courses for GATE exam
|
|
Similar GATE Doubts
A tractor PTO operated 4-disc rotary mower is harvesting with a forward speed of 3.5 km h-1. The cutting circle diameter and rpm of each disc are 60 cm and 1400, respectively. The peak cutting force experienced by each rotary disc is 110 N. The peak overall motion resistance is found to be 3.6 kN. If the overall power conversion efficiency of the tractor is 82%, required peak engine brake power in kW will be __________Correct answer is between '27.0,28.5'. Can you explain this answer?
Question Description
A tractor PTO operated 4-disc rotary mower is harvesting with a forward speed of 3.5 km h-1. The cutting circle diameter and rpm of each disc are 60 cm and 1400, respectively. The peak cutting force experienced by each rotary disc is 110 N. The peak overall motion resistance is found to be 3.6 kN. If the overall power conversion efficiency of the tractor is 82%, required peak engine brake power in kW will be __________Correct answer is between '27.0,28.5'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A tractor PTO operated 4-disc rotary mower is harvesting with a forward speed of 3.5 km h-1. The cutting circle diameter and rpm of each disc are 60 cm and 1400, respectively. The peak cutting force experienced by each rotary disc is 110 N. The peak overall motion resistance is found to be 3.6 kN. If the overall power conversion efficiency of the tractor is 82%, required peak engine brake power in kW will be __________Correct answer is between '27.0,28.5'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A tractor PTO operated 4-disc rotary mower is harvesting with a forward speed of 3.5 km h-1. The cutting circle diameter and rpm of each disc are 60 cm and 1400, respectively. The peak cutting force experienced by each rotary disc is 110 N. The peak overall motion resistance is found to be 3.6 kN. If the overall power conversion efficiency of the tractor is 82%, required peak engine brake power in kW will be __________Correct answer is between '27.0,28.5'. Can you explain this answer?.
A tractor PTO operated 4-disc rotary mower is harvesting with a forward speed of 3.5 km h-1. The cutting circle diameter and rpm of each disc are 60 cm and 1400, respectively. The peak cutting force experienced by each rotary disc is 110 N. The peak overall motion resistance is found to be 3.6 kN. If the overall power conversion efficiency of the tractor is 82%, required peak engine brake power in kW will be __________Correct answer is between '27.0,28.5'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A tractor PTO operated 4-disc rotary mower is harvesting with a forward speed of 3.5 km h-1. The cutting circle diameter and rpm of each disc are 60 cm and 1400, respectively. The peak cutting force experienced by each rotary disc is 110 N. The peak overall motion resistance is found to be 3.6 kN. If the overall power conversion efficiency of the tractor is 82%, required peak engine brake power in kW will be __________Correct answer is between '27.0,28.5'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A tractor PTO operated 4-disc rotary mower is harvesting with a forward speed of 3.5 km h-1. The cutting circle diameter and rpm of each disc are 60 cm and 1400, respectively. The peak cutting force experienced by each rotary disc is 110 N. The peak overall motion resistance is found to be 3.6 kN. If the overall power conversion efficiency of the tractor is 82%, required peak engine brake power in kW will be __________Correct answer is between '27.0,28.5'. Can you explain this answer?.
Solutions for A tractor PTO operated 4-disc rotary mower is harvesting with a forward speed of 3.5 km h-1. The cutting circle diameter and rpm of each disc are 60 cm and 1400, respectively. The peak cutting force experienced by each rotary disc is 110 N. The peak overall motion resistance is found to be 3.6 kN. If the overall power conversion efficiency of the tractor is 82%, required peak engine brake power in kW will be __________Correct answer is between '27.0,28.5'. Can you explain this answer? in English & in Hindi are available as part of our courses for GATE.
Download more important topics, notes, lectures and mock test series for GATE Exam by signing up for free.
Here you can find the meaning of A tractor PTO operated 4-disc rotary mower is harvesting with a forward speed of 3.5 km h-1. The cutting circle diameter and rpm of each disc are 60 cm and 1400, respectively. The peak cutting force experienced by each rotary disc is 110 N. The peak overall motion resistance is found to be 3.6 kN. If the overall power conversion efficiency of the tractor is 82%, required peak engine brake power in kW will be __________Correct answer is between '27.0,28.5'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A tractor PTO operated 4-disc rotary mower is harvesting with a forward speed of 3.5 km h-1. The cutting circle diameter and rpm of each disc are 60 cm and 1400, respectively. The peak cutting force experienced by each rotary disc is 110 N. The peak overall motion resistance is found to be 3.6 kN. If the overall power conversion efficiency of the tractor is 82%, required peak engine brake power in kW will be __________Correct answer is between '27.0,28.5'. Can you explain this answer?, a detailed solution for A tractor PTO operated 4-disc rotary mower is harvesting with a forward speed of 3.5 km h-1. The cutting circle diameter and rpm of each disc are 60 cm and 1400, respectively. The peak cutting force experienced by each rotary disc is 110 N. The peak overall motion resistance is found to be 3.6 kN. If the overall power conversion efficiency of the tractor is 82%, required peak engine brake power in kW will be __________Correct answer is between '27.0,28.5'. Can you explain this answer? has been provided alongside types of A tractor PTO operated 4-disc rotary mower is harvesting with a forward speed of 3.5 km h-1. The cutting circle diameter and rpm of each disc are 60 cm and 1400, respectively. The peak cutting force experienced by each rotary disc is 110 N. The peak overall motion resistance is found to be 3.6 kN. If the overall power conversion efficiency of the tractor is 82%, required peak engine brake power in kW will be __________Correct answer is between '27.0,28.5'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A tractor PTO operated 4-disc rotary mower is harvesting with a forward speed of 3.5 km h-1. The cutting circle diameter and rpm of each disc are 60 cm and 1400, respectively. The peak cutting force experienced by each rotary disc is 110 N. The peak overall motion resistance is found to be 3.6 kN. If the overall power conversion efficiency of the tractor is 82%, required peak engine brake power in kW will be __________Correct answer is between '27.0,28.5'. Can you explain this answer? tests, examples and also practice GATE tests.
|
|
Explore Courses for GATE exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup