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An engine absorbs heat at temperature of 1000 K and rejects heat at 600 K. If the engine operates at maximum possible efficiency, the amount of work performed by the engine for 200 J heat input is
Select one:
Select one:
- a)1200J
- b)400J
- c)1600J
- d)80J
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
An engine absorbs heat at temperature of 1000 K and rejects heat at 60...
Given data:
Temperature of heat input (Th) = 1000 K
Temperature of heat rejection (Tc) = 600 K
Heat input (Qh) = 200 J
Efficiency of the engine (η) can be calculated using the Carnot efficiency formula:
η = 1 - (Tc/Th)
Calculating the efficiency:
η = 1 - (600/1000) = 1 - 0.6 = 0.4
The efficiency of the engine is 0.4, which means that only 40% of the heat input is converted into work. Therefore, the amount of work performed by the engine can be calculated using the equation:
Work done (W) = η * Qh
Calculating the work done:
W = 0.4 * 200 = 80 J
However, the given options do not include the answer of 80 J. Therefore, we need to consider the fact that the engine operates at maximum possible efficiency.
If an engine operates at maximum possible efficiency, it is called a Carnot engine. The Carnot engine follows the Carnot cycle, which consists of a reversible isothermal expansion and a reversible adiabatic expansion.
In a Carnot engine, the work done can be calculated using the formula:
W = Qh - Qc
where Qh is the heat input and Qc is the heat rejected.
Calculating the work done using the Carnot engine formula:
W = 200 J - (600 K/1000 K) * 200 J = 200 J - 120 J = 80 J
Therefore, the amount of work performed by the engine for 200 J heat input is 80 J.
Temperature of heat input (Th) = 1000 K
Temperature of heat rejection (Tc) = 600 K
Heat input (Qh) = 200 J
Efficiency of the engine (η) can be calculated using the Carnot efficiency formula:
η = 1 - (Tc/Th)
Calculating the efficiency:
η = 1 - (600/1000) = 1 - 0.6 = 0.4
The efficiency of the engine is 0.4, which means that only 40% of the heat input is converted into work. Therefore, the amount of work performed by the engine can be calculated using the equation:
Work done (W) = η * Qh
Calculating the work done:
W = 0.4 * 200 = 80 J
However, the given options do not include the answer of 80 J. Therefore, we need to consider the fact that the engine operates at maximum possible efficiency.
If an engine operates at maximum possible efficiency, it is called a Carnot engine. The Carnot engine follows the Carnot cycle, which consists of a reversible isothermal expansion and a reversible adiabatic expansion.
In a Carnot engine, the work done can be calculated using the formula:
W = Qh - Qc
where Qh is the heat input and Qc is the heat rejected.
Calculating the work done using the Carnot engine formula:
W = 200 J - (600 K/1000 K) * 200 J = 200 J - 120 J = 80 J
Therefore, the amount of work performed by the engine for 200 J heat input is 80 J.
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An engine absorbs heat at temperature of 1000 K and rejects heat at 600 K. If the engine operates at maximum possible efficiency, the amount of work performed by the engine for 200 J heat input isSelect one:a)1200Jb)400Jc)1600Jd)80JCorrect answer is option 'D'. Can you explain this answer?
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An engine absorbs heat at temperature of 1000 K and rejects heat at 600 K. If the engine operates at maximum possible efficiency, the amount of work performed by the engine for 200 J heat input isSelect one:a)1200Jb)400Jc)1600Jd)80JCorrect answer is option 'D'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about An engine absorbs heat at temperature of 1000 K and rejects heat at 600 K. If the engine operates at maximum possible efficiency, the amount of work performed by the engine for 200 J heat input isSelect one:a)1200Jb)400Jc)1600Jd)80JCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An engine absorbs heat at temperature of 1000 K and rejects heat at 600 K. If the engine operates at maximum possible efficiency, the amount of work performed by the engine for 200 J heat input isSelect one:a)1200Jb)400Jc)1600Jd)80JCorrect answer is option 'D'. Can you explain this answer?.
An engine absorbs heat at temperature of 1000 K and rejects heat at 600 K. If the engine operates at maximum possible efficiency, the amount of work performed by the engine for 200 J heat input isSelect one:a)1200Jb)400Jc)1600Jd)80JCorrect answer is option 'D'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about An engine absorbs heat at temperature of 1000 K and rejects heat at 600 K. If the engine operates at maximum possible efficiency, the amount of work performed by the engine for 200 J heat input isSelect one:a)1200Jb)400Jc)1600Jd)80JCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An engine absorbs heat at temperature of 1000 K and rejects heat at 600 K. If the engine operates at maximum possible efficiency, the amount of work performed by the engine for 200 J heat input isSelect one:a)1200Jb)400Jc)1600Jd)80JCorrect answer is option 'D'. Can you explain this answer?.
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