Calculation of no of ozone molecules and oxygen atoms:


Given, the mass of oxygen gas, m = 3.2 g


The molar mass of oxygen gas, M = 32 g/mol


Therefore, the number of oxygen atoms present in 3.2 g of oxygen gas is given by:


n = m/M = 3.2/32 = 0.1 mol


Since ozone has three oxygen atoms in each molecule, the number of ozone molecules present in the sample is also 0.1 mol.


Therefore, the number of ozone molecules present in the sample is 0.1 x 6.02 x 10^23 = 6.02 x 10^22 molecules.

Calculation of volume of ozone gas at STP:


At STP, the pressure (P) is 1 atm and the temperature (T) is 273 K.


The volume (V) of 1 mole of any gas at STP is 22.4 L.


Therefore, the volume of 0.1 mole of ozone gas at STP is given by:


V = n x Vm = 0.1 x 22.4 = 2.24 L


Therefore, the volume of ozone gas at STP is 2.24 L.

Calculation of mass of ozone gas at STP:


The molar mass of ozone is 48 g/mol.


Therefore, the mass (m) of 0.1 mole of ozone gas is given by:


m = n x M = 0.1 x 48 = 4.8 g


Therefore, the mass of ozone gas at STP is 4.8 g.

Explanation:


The given problem required us to find the number of ozone molecules present in a sample and the volume and mass of ozone gas at STP. We first calculated the number of oxygen atoms present in 3.2 g of oxygen gas by using the molar mass of oxygen gas. Since ozone has three oxygen atoms in each molecule, the number of ozone molecules present in the sample is also 0.1 mol. We then used the volume of 1 mole of any gas at STP to calculate the volume of 0.1 mole of ozone gas at STP. Finally, we used the molar mass of ozone to calculate the mass of 0.1 mole of ozone gas at STP.

Ggh