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896ml of a mixture of CO and CO2 weigh 1.28g at NTP. Calculate the volume of CO2 in the mixture?
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896ml of a mixture of CO and CO2 weigh 1.28g at NTP. Calculate the vol...
Calculation of CO2 volume in the mixture
To calculate the volume of CO2 in the mixture, we need to first understand the properties of CO and CO2 and how they behave under NTP (Normal Temperature and Pressure) conditions.
Properties of CO and CO2
- CO is a colorless, odorless gas that is toxic in nature.
- CO2 is a colorless gas that is non-toxic but can cause suffocation in high concentrations.
- Under NTP conditions, the density of CO is 1.25 g/L and the density of CO2 is 1.98 g/L.
Calculating the volume of CO and CO2 in the mixture
Given that the mixture of CO and CO2 weighs 1.28 g at NTP, we can calculate the total volume of the mixture using the formula:
Volume = Mass/Density
Therefore, the total volume of the mixture is:
Volume = 1.28 g/(1.25 g/L + 1.98 g/L) = 0.368 L
Next, we need to calculate the volume of CO2 in the mixture. To do this, we can use the fact that the mass of CO in the mixture is:
Mass of CO = Volume of CO x Density of CO = (0.368 - Volume of CO2) x 1.25 g/L
Substituting the value of the total volume of the mixture and simplifying the equation, we get:
(0.368 - Volume of CO2) x 1.25 g/L = 1.28 g - Mass of CO2
Now, we need to calculate the mass of CO2 in the mixture. To do this, we can use the fact that the mass of the mixture is the sum of the masses of CO and CO2:
Mass of mixture = Mass of CO + Mass of CO2
Substituting the values of the mass of CO and the total mass of the mixture, we get:
1.28 g = (0.368 - Volume of CO2) x 1.25 g/L + Mass of CO2
Simplifying the equation, we get:
Mass of CO2 = 1.28 g - (0.368 - Volume of CO2) x 1.25 g/L
Now, we can substitute the value of the mass of CO2 in the equation we derived earlier and solve for the volume of CO2 in the mixture:
(0.368 - Volume of CO2) x 1.25 g/L = 1.28 g - (0.368 - Volume of CO2) x 1.25 g/L
Simplifying the equation, we get:
Volume of CO2 = 0.205 L
Conclusion
Therefore, the volume of CO2 in the mixture is 0.205 L.
Community Answer
896ml of a mixture of CO and CO2 weigh 1.28g at NTP. Calculate the vol...
Let the weight of CO in the mixture be x g.
Total weight of mixture =1.28g
Weight of CO2=1.28−x
Moleculr weight of CO=28g
Molecular weight of CO2=44g
Moles of CO2 in the mixture =441.28−x
Moles of CO in the mixture =28x
At NTP, the volume occupied by 1 mole of a gas =22400mL
∴ 896 mL occupied by 224001×896=0.04 moles
∴ Total moles in the mixture = 0.04 moles
⇒ Moles of CO2+ Moles of CO=0.04
⇒441.28−x+28x=0.04
⇒35.84−28x+44x=49.28
⇒16x=13.44
⇒x=0.84
∴ Molecular weight of CO2=1.28−0.84=0.44g
∴ Moles of CO2 in the mixture =440.44=0.01 moles
∵ Volume occupied by 1 mole of CO2=22400mL
⇒ Volume occupied by 0.01 mole of CO2=22400×0.01=224mL
Hence, at NTP, 224 mL of CO2 is present in the mixture.
Total weight of mixture =1.28g
Weight of CO2=1.28−x
Moleculr weight of CO=28g
Molecular weight of CO2=44g
Moles of CO2 in the mixture =441.28−x
Moles of CO in the mixture =28x
At NTP, the volume occupied by 1 mole of a gas =22400mL
∴ 896 mL occupied by 224001×896=0.04 moles
∴ Total moles in the mixture = 0.04 moles
⇒ Moles of CO2+ Moles of CO=0.04
⇒441.28−x+28x=0.04
⇒35.84−28x+44x=49.28
⇒16x=13.44
⇒x=0.84
∴ Molecular weight of CO2=1.28−0.84=0.44g
∴ Moles of CO2 in the mixture =440.44=0.01 moles
∵ Volume occupied by 1 mole of CO2=22400mL
⇒ Volume occupied by 0.01 mole of CO2=22400×0.01=224mL
Hence, at NTP, 224 mL of CO2 is present in the mixture.
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896ml of a mixture of CO and CO2 weigh 1.28g at NTP. Calculate the volume of CO2 in the mixture?
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896ml of a mixture of CO and CO2 weigh 1.28g at NTP. Calculate the volume of CO2 in the mixture? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 896ml of a mixture of CO and CO2 weigh 1.28g at NTP. Calculate the volume of CO2 in the mixture? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 896ml of a mixture of CO and CO2 weigh 1.28g at NTP. Calculate the volume of CO2 in the mixture?.
896ml of a mixture of CO and CO2 weigh 1.28g at NTP. Calculate the volume of CO2 in the mixture? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 896ml of a mixture of CO and CO2 weigh 1.28g at NTP. Calculate the volume of CO2 in the mixture? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 896ml of a mixture of CO and CO2 weigh 1.28g at NTP. Calculate the volume of CO2 in the mixture?.
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