The coach of a cricket team buys 3 bats and 6 balls for ₹ 3900. Later,...
let the price of 1bat=x and price of one ball=y
case1:
3x+6y=3900
( dividing both sides by 3)
x+2y=1300--(1)
case2:
x+3y=1300--(2)
putting x=0 in(1)
3y=1300
y=650
algebraically solution for equation 1=(0, 650)
putting x=100 in (1)
2y=1200
y=600
x y
0 650
100 600
For eq(2)
by putting x=0
we get y=433.3
by putting x=100
we get y=400
x y
0 433.3
100 400
Graphically:
The coach of a cricket team buys 3 bats and 6 balls for ₹ 3900. Later,...
Algebraic representation:
Let the cost of one bat and one ball be x and y respectively.
Then, as per the given information,
3x + 6y = 3900 ...(1)
And,
1x + 3y = 1300 ...(2)
Geometric representation:
The given information can be represented geometrically as follows:
Consider a 2D plane, where x-axis represents the cost of one bat and y-axis represents the cost of one ball.
Then, equation (1) represents a line passing through the points (0,650) and (1300,0) on the plane.
Similarly, equation (2) represents a line passing through the points (0,433.33) and (1300,0) on the plane.
The solution to this system of equations (1) and (2) represents the point of intersection of these two lines, which gives the cost of one bat and one ball.
Solution:
Multiplying equation (2) by 2, we get:
2x + 6y = 2600
Subtracting this equation from equation (1), we get:
x = 1300
Substituting this value of x in equation (2), we get:
3y = 650
Thus, y = 216.67
Hence, the cost of one bat is ₹ 1300 and the cost of one ball is ₹ 216.67.
We can verify that these values satisfy both equations (1) and (2).
Conclusion:
The algebraic and geometric representations help us to solve the given problem in an organized and systematic way, which makes it easier to understand and interpret the solution.
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