Class 10 Exam > Class 10 Questions > A rocket is moving in a gravity free space wi...
Start Learning for Free
A rocket is moving in a gravity free space with a constant acceleration of 2 ms2 along x direction (see figure). The length of a chamber inside the rocket is 4 m. A ball is thrown from the left end of the chamber in x direction with a speed of 0.3 ms-1 relative to the rocket. At the same time, another ball is thrown in –x direction with a speed of 0.2 ms from right end relative to the rocket. The time in seconds when its the two balls hit each other is ?!?
Most Upvoted Answer
A rocket is moving in a gravity free space with a constant acceleratio...
Community Answer
A rocket is moving in a gravity free space with a constant acceleratio...
Problem Statement: A rocket is moving in a gravity-free space with a constant acceleration of 2 ms2 along the x direction. The length of a chamber inside the rocket is 4 m. A ball is thrown from the left end of the chamber in x direction with a speed of 0.3 ms-1 relative to the rocket. At the same time, another ball is thrown in –x direction with a speed of 0.2 ms-1 from the right end relative to the rocket. The time in seconds when the two balls hit each other is ?!? Explain in detail.
Solution:
To solve this problem, we need to find out the time at which the two balls meet. We can do this by using the equations of motion and relative velocity.
Step 1: Find the acceleration of the rocket
Given, the acceleration of the rocket is 2 ms-2.
Step 2: Find the time taken by the ball thrown in the x direction to reach the right end of the chamber.
From the equation of motion, we know that:
v = u + at
where,
v = final velocity = 0 (since the ball comes to rest at the right end)
u = initial velocity = 0.3 ms-1 (relative to the rocket)
a = acceleration of the rocket = 2 ms-2
t = time taken
Substituting the values in the above equation, we get:
0 = 0.3 + 2t
t = 0.15 s
Step 3: Find the time taken by the ball thrown in the -x direction to reach the left end of the chamber.
Using the same equation of motion as in step 2, we get:
0 = -0.2 + 2t
t = 0.1 s
Step 4: Find the relative velocity of the two balls.
The relative velocity of the two balls can be found by subtracting their velocities. Since one ball is moving in the x direction and the other in the -x direction, the relative velocity is the sum of their velocities.
Relative velocity = 0.3 + (-0.2) = 0.1 ms-1
Step 5: Find the distance between the two balls.
The distance between the two balls is the length of the chamber, which is 4 m.
Step 6: Find the time taken by the two balls to meet.
Using the formula:
Distance = Relative velocity * Time
we get:
4 = 0.1 * Time
Time = 40 s
Therefore, the time taken by the two balls to meet is 40 s.
Solution:
To solve this problem, we need to find out the time at which the two balls meet. We can do this by using the equations of motion and relative velocity.
Step 1: Find the acceleration of the rocket
Given, the acceleration of the rocket is 2 ms-2.
Step 2: Find the time taken by the ball thrown in the x direction to reach the right end of the chamber.
From the equation of motion, we know that:
v = u + at
where,
v = final velocity = 0 (since the ball comes to rest at the right end)
u = initial velocity = 0.3 ms-1 (relative to the rocket)
a = acceleration of the rocket = 2 ms-2
t = time taken
Substituting the values in the above equation, we get:
0 = 0.3 + 2t
t = 0.15 s
Step 3: Find the time taken by the ball thrown in the -x direction to reach the left end of the chamber.
Using the same equation of motion as in step 2, we get:
0 = -0.2 + 2t
t = 0.1 s
Step 4: Find the relative velocity of the two balls.
The relative velocity of the two balls can be found by subtracting their velocities. Since one ball is moving in the x direction and the other in the -x direction, the relative velocity is the sum of their velocities.
Relative velocity = 0.3 + (-0.2) = 0.1 ms-1
Step 5: Find the distance between the two balls.
The distance between the two balls is the length of the chamber, which is 4 m.
Step 6: Find the time taken by the two balls to meet.
Using the formula:
Distance = Relative velocity * Time
we get:
4 = 0.1 * Time
Time = 40 s
Therefore, the time taken by the two balls to meet is 40 s.
Attention Class 10 Students!
To make sure you are not studying endlessly, EduRev has designed Class 10 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 10.
|
Explore Courses for Class 10 exam
|
|
Similar Class 10 Doubts
Top Courses for Class 10View all
A rocket is moving in a gravity free space with a constant acceleration of 2 ms2 along x direction (see figure). The length of a chamber inside the rocket is 4 m. A ball is thrown from the left end of the chamber in x direction with a speed of 0.3 ms-1 relative to the rocket. At the same time, another ball is thrown in –x direction with a speed of 0.2 ms from right end relative to the rocket. The time in seconds when its the two balls hit each other is ?!?
Question Description
A rocket is moving in a gravity free space with a constant acceleration of 2 ms2 along x direction (see figure). The length of a chamber inside the rocket is 4 m. A ball is thrown from the left end of the chamber in x direction with a speed of 0.3 ms-1 relative to the rocket. At the same time, another ball is thrown in –x direction with a speed of 0.2 ms from right end relative to the rocket. The time in seconds when its the two balls hit each other is ?!? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about A rocket is moving in a gravity free space with a constant acceleration of 2 ms2 along x direction (see figure). The length of a chamber inside the rocket is 4 m. A ball is thrown from the left end of the chamber in x direction with a speed of 0.3 ms-1 relative to the rocket. At the same time, another ball is thrown in –x direction with a speed of 0.2 ms from right end relative to the rocket. The time in seconds when its the two balls hit each other is ?!? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A rocket is moving in a gravity free space with a constant acceleration of 2 ms2 along x direction (see figure). The length of a chamber inside the rocket is 4 m. A ball is thrown from the left end of the chamber in x direction with a speed of 0.3 ms-1 relative to the rocket. At the same time, another ball is thrown in –x direction with a speed of 0.2 ms from right end relative to the rocket. The time in seconds when its the two balls hit each other is ?!?.
A rocket is moving in a gravity free space with a constant acceleration of 2 ms2 along x direction (see figure). The length of a chamber inside the rocket is 4 m. A ball is thrown from the left end of the chamber in x direction with a speed of 0.3 ms-1 relative to the rocket. At the same time, another ball is thrown in –x direction with a speed of 0.2 ms from right end relative to the rocket. The time in seconds when its the two balls hit each other is ?!? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about A rocket is moving in a gravity free space with a constant acceleration of 2 ms2 along x direction (see figure). The length of a chamber inside the rocket is 4 m. A ball is thrown from the left end of the chamber in x direction with a speed of 0.3 ms-1 relative to the rocket. At the same time, another ball is thrown in –x direction with a speed of 0.2 ms from right end relative to the rocket. The time in seconds when its the two balls hit each other is ?!? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A rocket is moving in a gravity free space with a constant acceleration of 2 ms2 along x direction (see figure). The length of a chamber inside the rocket is 4 m. A ball is thrown from the left end of the chamber in x direction with a speed of 0.3 ms-1 relative to the rocket. At the same time, another ball is thrown in –x direction with a speed of 0.2 ms from right end relative to the rocket. The time in seconds when its the two balls hit each other is ?!?.
Solutions for A rocket is moving in a gravity free space with a constant acceleration of 2 ms2 along x direction (see figure). The length of a chamber inside the rocket is 4 m. A ball is thrown from the left end of the chamber in x direction with a speed of 0.3 ms-1 relative to the rocket. At the same time, another ball is thrown in –x direction with a speed of 0.2 ms from right end relative to the rocket. The time in seconds when its the two balls hit each other is ?!? in English & in Hindi are available as part of our courses for Class 10.
Download more important topics, notes, lectures and mock test series for Class 10 Exam by signing up for free.
Here you can find the meaning of A rocket is moving in a gravity free space with a constant acceleration of 2 ms2 along x direction (see figure). The length of a chamber inside the rocket is 4 m. A ball is thrown from the left end of the chamber in x direction with a speed of 0.3 ms-1 relative to the rocket. At the same time, another ball is thrown in –x direction with a speed of 0.2 ms from right end relative to the rocket. The time in seconds when its the two balls hit each other is ?!? defined & explained in the simplest way possible. Besides giving the explanation of
A rocket is moving in a gravity free space with a constant acceleration of 2 ms2 along x direction (see figure). The length of a chamber inside the rocket is 4 m. A ball is thrown from the left end of the chamber in x direction with a speed of 0.3 ms-1 relative to the rocket. At the same time, another ball is thrown in –x direction with a speed of 0.2 ms from right end relative to the rocket. The time in seconds when its the two balls hit each other is ?!?, a detailed solution for A rocket is moving in a gravity free space with a constant acceleration of 2 ms2 along x direction (see figure). The length of a chamber inside the rocket is 4 m. A ball is thrown from the left end of the chamber in x direction with a speed of 0.3 ms-1 relative to the rocket. At the same time, another ball is thrown in –x direction with a speed of 0.2 ms from right end relative to the rocket. The time in seconds when its the two balls hit each other is ?!? has been provided alongside types of A rocket is moving in a gravity free space with a constant acceleration of 2 ms2 along x direction (see figure). The length of a chamber inside the rocket is 4 m. A ball is thrown from the left end of the chamber in x direction with a speed of 0.3 ms-1 relative to the rocket. At the same time, another ball is thrown in –x direction with a speed of 0.2 ms from right end relative to the rocket. The time in seconds when its the two balls hit each other is ?!? theory, EduRev gives you an
ample number of questions to practice A rocket is moving in a gravity free space with a constant acceleration of 2 ms2 along x direction (see figure). The length of a chamber inside the rocket is 4 m. A ball is thrown from the left end of the chamber in x direction with a speed of 0.3 ms-1 relative to the rocket. At the same time, another ball is thrown in –x direction with a speed of 0.2 ms from right end relative to the rocket. The time in seconds when its the two balls hit each other is ?!? tests, examples and also practice Class 10 tests.
|
|
Explore Courses for Class 10 exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup