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A rocket is moving in a gravity free space with a constant acceleration of 2 ms2 along x direction (see figure). The length of a chamber inside the rocket is 4 m. A ball is thrown from the left end of the chamber in x direction with a speed of 0.3 ms-1 relative to the rocket. At the same time, another ball is thrown in –x direction with a speed of 0.2 ms from right end relative to the rocket. The time in seconds when its the two balls hit each other is ?!?
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Problem Statement: A rocket is moving in a gravity-free space with a constant acceleration of 2 ms2 along the x direction. The length of a chamber inside the rocket is 4 m. A ball is thrown from the left end of the chamber in x direction with a speed of 0.3 ms-1 relative to the rocket. At the same time, another ball is thrown in –x direction with a speed of 0.2 ms-1 from the right end relative to the rocket. The time in seconds when the two balls hit each other is ?!? Explain in detail.
Solution:
To solve this problem, we need to find out the time at which the two balls meet. We can do this by using the equations of motion and relative velocity.
Step 1: Find the acceleration of the rocket
Given, the acceleration of the rocket is 2 ms-2.
Step 2: Find the time taken by the ball thrown in the x direction to reach the right end of the chamber.
From the equation of motion, we know that:
v = u + at
where,
v = final velocity = 0 (since the ball comes to rest at the right end)
u = initial velocity = 0.3 ms-1 (relative to the rocket)
a = acceleration of the rocket = 2 ms-2
t = time taken
Substituting the values in the above equation, we get:
0 = 0.3 + 2t
t = 0.15 s
Step 3: Find the time taken by the ball thrown in the -x direction to reach the left end of the chamber.
Using the same equation of motion as in step 2, we get:
0 = -0.2 + 2t
t = 0.1 s
Step 4: Find the relative velocity of the two balls.
The relative velocity of the two balls can be found by subtracting their velocities. Since one ball is moving in the x direction and the other in the -x direction, the relative velocity is the sum of their velocities.
Relative velocity = 0.3 + (-0.2) = 0.1 ms-1
Step 5: Find the distance between the two balls.
The distance between the two balls is the length of the chamber, which is 4 m.
Step 6: Find the time taken by the two balls to meet.
Using the formula:
Distance = Relative velocity * Time
we get:
4 = 0.1 * Time
Time = 40 s
Therefore, the time taken by the two balls to meet is 40 s.
Solution:
To solve this problem, we need to find out the time at which the two balls meet. We can do this by using the equations of motion and relative velocity.
Step 1: Find the acceleration of the rocket
Given, the acceleration of the rocket is 2 ms-2.
Step 2: Find the time taken by the ball thrown in the x direction to reach the right end of the chamber.
From the equation of motion, we know that:
v = u + at
where,
v = final velocity = 0 (since the ball comes to rest at the right end)
u = initial velocity = 0.3 ms-1 (relative to the rocket)
a = acceleration of the rocket = 2 ms-2
t = time taken
Substituting the values in the above equation, we get:
0 = 0.3 + 2t
t = 0.15 s
Step 3: Find the time taken by the ball thrown in the -x direction to reach the left end of the chamber.
Using the same equation of motion as in step 2, we get:
0 = -0.2 + 2t
t = 0.1 s
Step 4: Find the relative velocity of the two balls.
The relative velocity of the two balls can be found by subtracting their velocities. Since one ball is moving in the x direction and the other in the -x direction, the relative velocity is the sum of their velocities.
Relative velocity = 0.3 + (-0.2) = 0.1 ms-1
Step 5: Find the distance between the two balls.
The distance between the two balls is the length of the chamber, which is 4 m.
Step 6: Find the time taken by the two balls to meet.
Using the formula:
Distance = Relative velocity * Time
we get:
4 = 0.1 * Time
Time = 40 s
Therefore, the time taken by the two balls to meet is 40 s.
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A rocket is moving in a gravity free space with a constant acceleration of 2 ms2 along x direction (see figure). The length of a chamber inside the rocket is 4 m. A ball is thrown from the left end of the chamber in x direction with a speed of 0.3 ms-1 relative to the rocket. At the same time, another ball is thrown in –x direction with a speed of 0.2 ms from right end relative to the rocket. The time in seconds when its the two balls hit each other is ?!?
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A rocket is moving in a gravity free space with a constant acceleration of 2 ms2 along x direction (see figure). The length of a chamber inside the rocket is 4 m. A ball is thrown from the left end of the chamber in x direction with a speed of 0.3 ms-1 relative to the rocket. At the same time, another ball is thrown in –x direction with a speed of 0.2 ms from right end relative to the rocket. The time in seconds when its the two balls hit each other is ?!? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about A rocket is moving in a gravity free space with a constant acceleration of 2 ms2 along x direction (see figure). The length of a chamber inside the rocket is 4 m. A ball is thrown from the left end of the chamber in x direction with a speed of 0.3 ms-1 relative to the rocket. At the same time, another ball is thrown in –x direction with a speed of 0.2 ms from right end relative to the rocket. The time in seconds when its the two balls hit each other is ?!? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A rocket is moving in a gravity free space with a constant acceleration of 2 ms2 along x direction (see figure). The length of a chamber inside the rocket is 4 m. A ball is thrown from the left end of the chamber in x direction with a speed of 0.3 ms-1 relative to the rocket. At the same time, another ball is thrown in –x direction with a speed of 0.2 ms from right end relative to the rocket. The time in seconds when its the two balls hit each other is ?!?.
A rocket is moving in a gravity free space with a constant acceleration of 2 ms2 along x direction (see figure). The length of a chamber inside the rocket is 4 m. A ball is thrown from the left end of the chamber in x direction with a speed of 0.3 ms-1 relative to the rocket. At the same time, another ball is thrown in –x direction with a speed of 0.2 ms from right end relative to the rocket. The time in seconds when its the two balls hit each other is ?!? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about A rocket is moving in a gravity free space with a constant acceleration of 2 ms2 along x direction (see figure). The length of a chamber inside the rocket is 4 m. A ball is thrown from the left end of the chamber in x direction with a speed of 0.3 ms-1 relative to the rocket. At the same time, another ball is thrown in –x direction with a speed of 0.2 ms from right end relative to the rocket. The time in seconds when its the two balls hit each other is ?!? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A rocket is moving in a gravity free space with a constant acceleration of 2 ms2 along x direction (see figure). The length of a chamber inside the rocket is 4 m. A ball is thrown from the left end of the chamber in x direction with a speed of 0.3 ms-1 relative to the rocket. At the same time, another ball is thrown in –x direction with a speed of 0.2 ms from right end relative to the rocket. The time in seconds when its the two balls hit each other is ?!?.
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