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A rocket is fired vertically from the ground . It moves upwards with a constant acceleration 10m/s^2 for 30 secs after which the fuel is consumed. After what time from the instant of firing, the rocket will attain the maximum height ?
Most Upvoted Answer
A rocket is fired vertically from the ground . It moves upwards with a...
Calculating the time taken by the rocket to attain maximum height

To calculate the time taken by the rocket to attain maximum height, we need to find the point where the velocity of the rocket becomes zero. This is because the maximum height is achieved when the velocity of the rocket becomes zero and starts falling back due to gravity.

Using the kinematic equation to find the time taken

We can use the kinematic equation:

v = u + at

where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time taken.

For the rocket, the final velocity is zero as it comes to a stop at the maximum height. The initial velocity is given as zero as the rocket is fired from rest. The acceleration is given as 10 m/s^2 as it moves upwards with a constant acceleration.

Substituting the values, we get:

0 = 0 + 10t

Simplifying, we get:

t = 0 seconds

This shows that it takes zero seconds for the rocket to reach the maximum height.

Explaining the reason behind the result

This result might seem counterintuitive, but it is because we have only considered the time taken for the rocket to come to a stop. The rocket will continue to move upwards for some time after it has come to a stop, but it will eventually start falling back to the ground due to gravity.

The maximum height is achieved when the rocket reaches the point where it starts falling back. This point is determined by the time taken for the rocket to come to a stop, which we have calculated as zero seconds.

Therefore, the time taken for the rocket to attain maximum height is zero seconds.
Community Answer
A rocket is fired vertically from the ground . It moves upwards with a...
S=ut+1/2(at�)

s=4500m

Putting in v�-u�=2as

We get v=300m/s

Now a=-10m/s� after  the fuel is consumed

So v=u-gt

We get t=30s

Total time for which rocket is ascending=30s+30s=60s
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A rocket is fired vertically from the ground . It moves upwards with a constant acceleration 10m/s^2 for 30 secs after which the fuel is consumed. After what time from the instant of firing, the rocket will attain the maximum height ?
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