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two cars A and N were at rest initially. if A starts with uniform velocity of 40m /s and B starts with constant acceleration of 4m/s^2 then B will catch A in how many seconds
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two cars A and N were at rest initially. if A starts with uniform velo...
Analysis of the situation:
- Car A is moving with a constant velocity of 40 m/s.
- Car B is accelerating at a rate of 4 m/s^2.

Determining when Car B catches up to Car A:
- To find out when Car B catches up to Car A, we need to determine the time it takes for Car B to reach the same position as Car A.
- We can use the basic kinematic equation:
\[v = u + at\]
where:
- \(v\) is the final velocity
- \(u\) is the initial velocity
- \(a\) is the acceleration
- \(t\) is the time taken
- For Car A:
\[v_{A} = 40 \, m/s\]
\[u_{A} = 0 \, m/s\]
\[a_{A} = 0 \, m/s^2\]
- For Car B:
\[u_{B} = 0 \, m/s\]
\[a_{B} = 4 \, m/s^2\]
- Let's calculate the time it takes for Car B to catch up to Car A:
\[40 = 0 + 4t\]
\[t = 10 \, s\]

Conclusion:
- Car B will catch up to Car A in 10 seconds.
Community Answer
two cars A and N were at rest initially. if A starts with uniform velo...
I think question is incomplete ....
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two cars A and N were at rest initially. if A starts with uniform velocity of 40m /s and B starts with constant acceleration of 4m/s^2 then B will catch A in how many seconds
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