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The limiting current (in μA) from the reduction of 3 × 10-4 M Pb2+, using a dropping mercury electrode (DME) with characteristics, m = 3.0 mg s-1 and t = 3s, is (diffusion coefficient of Pb2+ = 1.2 × 10-5 cm2 s-1) _______________Correct answer is between '3.5,3.8'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared
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The limiting current (in μA) from the reduction of 3 × 10-4 M Pb2+, using a dropping mercury electrode (DME) with characteristics, m = 3.0 mg s-1 and t = 3s, is (diffusion coefficient of Pb2+ = 1.2 × 10-5 cm2 s-1) _______________Correct answer is between '3.5,3.8'. Can you explain this answer?, a detailed solution for The limiting current (in μA) from the reduction of 3 × 10-4 M Pb2+, using a dropping mercury electrode (DME) with characteristics, m = 3.0 mg s-1 and t = 3s, is (diffusion coefficient of Pb2+ = 1.2 × 10-5 cm2 s-1) _______________Correct answer is between '3.5,3.8'. Can you explain this answer? has been provided alongside types of The limiting current (in μA) from the reduction of 3 × 10-4 M Pb2+, using a dropping mercury electrode (DME) with characteristics, m = 3.0 mg s-1 and t = 3s, is (diffusion coefficient of Pb2+ = 1.2 × 10-5 cm2 s-1) _______________Correct answer is between '3.5,3.8'. Can you explain this answer? theory, EduRev gives you an
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