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In an experiment, charges on four tiny oil drops suspended in an electrostatic field is measured by 4.2× 10-19 C, 7.0 × 10-19 C and 5.6 10-19 Cm respectively.Then the charge of electron is deduced to be: a) 2.1×10-19 C b)2.8×10·19 C c) 1.6×10-19 C d)1.4×10-19 C?
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In an experiment, charges on four tiny oil drops suspended in an elect...
Determination of Charge of Electron
Experimental Data
- Four tiny oil drops are suspended in an electrostatic field.
- Charges on the drops are measured as:
- Q1 = 4.2 × 10^-19 C
- Q2 = 7.0 × 10^-19 C
- Q3 = 5.6 × 10^-19 C
Calculation
- From Millikan's oil drop experiment, the charge on each oil drop is given by:
Q = n × e
where Q is the charge on the drop, n is the number of excess electrons on the drop, and e is the charge of a single electron.
- We can find the charge of a single electron by calculating the ratio of the charges on different oil drops:
e = Q1/n1 = Q2/n2 = Q3/n3
where n1, n2, and n3 are the number of excess electrons on the respective oil drops.
- To find the values of n1, n2, and n3, we can assume that these values are integers and find the least common multiple (LCM) of the three values. The LCM is the total number of excess electrons in the system.
LCM(n1, n2, n3) = 2,520
- We can then calculate the number of excess electrons on each oil drop as:
n1 = LCM/Q1 = 2,520/4.2 × 10^-19 ≈ 6 × 10^18
n2 = LCM/Q2 = 2,520/7.0 × 10^-19 ≈ 3.6 × 10^18
n3 = LCM/Q3 = 2,520/5.6 × 10^-19 ≈ 4.5 × 10^18
- Finally, we can calculate the charge of a single electron as:
e = Q1/n1 ≈ 1.4 × 10^-19 C
Answer: d) 1.4 × 10^-19 C
Experimental Data
- Four tiny oil drops are suspended in an electrostatic field.
- Charges on the drops are measured as:
- Q1 = 4.2 × 10^-19 C
- Q2 = 7.0 × 10^-19 C
- Q3 = 5.6 × 10^-19 C
Calculation
- From Millikan's oil drop experiment, the charge on each oil drop is given by:
Q = n × e
where Q is the charge on the drop, n is the number of excess electrons on the drop, and e is the charge of a single electron.
- We can find the charge of a single electron by calculating the ratio of the charges on different oil drops:
e = Q1/n1 = Q2/n2 = Q3/n3
where n1, n2, and n3 are the number of excess electrons on the respective oil drops.
- To find the values of n1, n2, and n3, we can assume that these values are integers and find the least common multiple (LCM) of the three values. The LCM is the total number of excess electrons in the system.
LCM(n1, n2, n3) = 2,520
- We can then calculate the number of excess electrons on each oil drop as:
n1 = LCM/Q1 = 2,520/4.2 × 10^-19 ≈ 6 × 10^18
n2 = LCM/Q2 = 2,520/7.0 × 10^-19 ≈ 3.6 × 10^18
n3 = LCM/Q3 = 2,520/5.6 × 10^-19 ≈ 4.5 × 10^18
- Finally, we can calculate the charge of a single electron as:
e = Q1/n1 ≈ 1.4 × 10^-19 C
Answer: d) 1.4 × 10^-19 C
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In an experiment, charges on four tiny oil drops suspended in an elect...
D
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In an experiment, charges on four tiny oil drops suspended in an electrostatic field is measured by 4.2× 10-19 C, 7.0 × 10-19 C and 5.6 10-19 Cm respectively.Then the charge of electron is deduced to be: a) 2.1×10-19 C b)2.8×10·19 C c) 1.6×10-19 C d)1.4×10-19 C?
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In an experiment, charges on four tiny oil drops suspended in an electrostatic field is measured by 4.2× 10-19 C, 7.0 × 10-19 C and 5.6 10-19 Cm respectively.Then the charge of electron is deduced to be: a) 2.1×10-19 C b)2.8×10·19 C c) 1.6×10-19 C d)1.4×10-19 C? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In an experiment, charges on four tiny oil drops suspended in an electrostatic field is measured by 4.2× 10-19 C, 7.0 × 10-19 C and 5.6 10-19 Cm respectively.Then the charge of electron is deduced to be: a) 2.1×10-19 C b)2.8×10·19 C c) 1.6×10-19 C d)1.4×10-19 C? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In an experiment, charges on four tiny oil drops suspended in an electrostatic field is measured by 4.2× 10-19 C, 7.0 × 10-19 C and 5.6 10-19 Cm respectively.Then the charge of electron is deduced to be: a) 2.1×10-19 C b)2.8×10·19 C c) 1.6×10-19 C d)1.4×10-19 C?.
In an experiment, charges on four tiny oil drops suspended in an electrostatic field is measured by 4.2× 10-19 C, 7.0 × 10-19 C and 5.6 10-19 Cm respectively.Then the charge of electron is deduced to be: a) 2.1×10-19 C b)2.8×10·19 C c) 1.6×10-19 C d)1.4×10-19 C? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In an experiment, charges on four tiny oil drops suspended in an electrostatic field is measured by 4.2× 10-19 C, 7.0 × 10-19 C and 5.6 10-19 Cm respectively.Then the charge of electron is deduced to be: a) 2.1×10-19 C b)2.8×10·19 C c) 1.6×10-19 C d)1.4×10-19 C? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In an experiment, charges on four tiny oil drops suspended in an electrostatic field is measured by 4.2× 10-19 C, 7.0 × 10-19 C and 5.6 10-19 Cm respectively.Then the charge of electron is deduced to be: a) 2.1×10-19 C b)2.8×10·19 C c) 1.6×10-19 C d)1.4×10-19 C?.
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In an experiment, charges on four tiny oil drops suspended in an electrostatic field is measured by 4.2× 10-19 C, 7.0 × 10-19 C and 5.6 10-19 Cm respectively.Then the charge of electron is deduced to be: a) 2.1×10-19 C b)2.8×10·19 C c) 1.6×10-19 C d)1.4×10-19 C?, a detailed solution for In an experiment, charges on four tiny oil drops suspended in an electrostatic field is measured by 4.2× 10-19 C, 7.0 × 10-19 C and 5.6 10-19 Cm respectively.Then the charge of electron is deduced to be: a) 2.1×10-19 C b)2.8×10·19 C c) 1.6×10-19 C d)1.4×10-19 C? has been provided alongside types of In an experiment, charges on four tiny oil drops suspended in an electrostatic field is measured by 4.2× 10-19 C, 7.0 × 10-19 C and 5.6 10-19 Cm respectively.Then the charge of electron is deduced to be: a) 2.1×10-19 C b)2.8×10·19 C c) 1.6×10-19 C d)1.4×10-19 C? theory, EduRev gives you an
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