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Read the following and answer the questions that follow. 
If 5 people are transferred from E to R and another independent set of 5 people are transferred back from R to E, then after this operation (Assume that the set transferred from R to E contains none from the set of students that came to R from E)
For question 3, what could be the minimum value of the average of class R?
  • a)
    25 
  • b)
    24.2 
  • c)
    22.4 
  • d)
    23
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Read the following and answer the questions that follow.If 5 people ar...
For the minimum possible value of R we will need the E to R transfer to be the lowest possible value while the R to E transfer must have the highest possible value.
Thus, E to R transfer -> 18* 5 while R to E transfer will be 31*5. Hence the answer is 22.4. 
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Most Upvoted Answer
Read the following and answer the questions that follow.If 5 people ar...
Minimum value of the average of class R:

To determine the minimum value of the average of class R after the given operation, we need to consider the worst-case scenario.

Step 1: Transferring 5 people from E to R
Initially, let's assume that class E has x students and class R has y students. After transferring 5 people from E to R, the number of students in R becomes y + 5, and the number of students in E becomes x - 5.

Step 2: Transferring another set of 5 people from R to E
In this step, we need to ensure that the set transferred from R to E contains none of the students that came to R from E. This means that we need to transfer 5 different students from R to E. After this transfer, the number of students in R becomes (y + 5) - 5 = y, and the number of students in E becomes (x - 5) + 5 = x.

Step 3: Calculating the minimum average of class R
To determine the minimum average of class R, we need to consider the worst-case scenario where the number of students in E is minimized and the number of students in R is maximized.

Let's assume that initially, class E has n students and class R has m students. In this worst-case scenario, after the given operation, class E will have (n - 5) students and class R will have (m + 5) students.

To calculate the minimum average of class R, we need to minimize the number of students in E and maximize the number of students in R. This can be achieved by minimizing the value of n and maximizing the value of m.

Final Calculation:
To calculate the minimum average of class R:
- Let's assume n = 5 (minimum possible value for class E)
- Let's assume m = 5 (maximum possible value for class R)

After the given operation, the number of students in E becomes (5 - 5) = 0, and the number of students in R becomes (5 + 5) = 10.

Therefore, the minimum average of class R is obtained by dividing the total number of students in R (10) by the number of students in R (10):

Minimum average of class R = 10/10 = 1

However, the options provided do not include 1 as a possible answer. The closest option is 22.4, which is not the correct answer based on the given explanation. Therefore, the correct answer cannot be determined from the options provided.
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Community Answer
Read the following and answer the questions that follow.If 5 people ar...
Total runs after 25 innings = 25 x 56= 1400
Since, after 26 innings average run is increased by 2, hence new average = 56+2 = 58
Now,
Total runs after 26 innings = 26 x 58 = 1508
Score in 26th inning = 1508 - 1400 = 108 runs.
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Read the following and answer the questions that follow.If 5 people are transferred from E to R and another independent set of 5 people are transferred back from R to E, then after this operation (Assume that the set transferred from R to E contains none from the set of students that came to R from E)For question 3, what could be the minimum value of the average of class R?a)25b)24.2c)22.4d)23Correct answer is option 'C'. Can you explain this answer?
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