The continuous random variable X is uniformly distributed with mean1 a...
Problem Statement
Given that the continuous random variable X is uniformly distributed with mean 1 and variance 3, find P(X > 0).
Solution
Let us first find the standard deviation of the random variable X.
- Given that variance of X is 3, we have Var(X) = 3
- Also, we know that the variance of a uniformly distributed random variable (with a and b as its limits) is given by:
Var(X) = (b - a)^2 / 12
- Substituting the values, we get:
3 = (b - a)^2 / 12
b - a = 2√3
Since the mean of X is 1, we have:
Mean(X) = (a + b) / 2 = 1
So, a + b = 2
Now, we can solve these two equations to get:
a = 1 - √3 and b = 1 + √3
Thus, the standard deviation of X is:
SD(X) = √Var(X) = √3
Now, we can calculate the required probability:
P(X > 0) = P(Z > (0 - 1) / √3) where Z is the standard normal random variable
= P(Z > -√3 / 3)
= P(Z < √3 / 3)
= 0.63 (from standard normal distribution table)
Conclusion
The probability that the continuous random variable X is greater than 0 is 0.63.