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The continuous random variable X is uniformly distributed with mean1 and variance 3, find P(X 0)?
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The continuous random variable X is uniformly distributed with mean1 a...
Problem Statement

Given that the continuous random variable X is uniformly distributed with mean 1 and variance 3, find P(X > 0).


Solution

Let us first find the standard deviation of the random variable X.



  • Given that variance of X is 3, we have Var(X) = 3

  • Also, we know that the variance of a uniformly distributed random variable (with a and b as its limits) is given by:



Var(X) = (b - a)^2 / 12



  • Substituting the values, we get:



3 = (b - a)^2 / 12

b - a = 2√3


Since the mean of X is 1, we have:

Mean(X) = (a + b) / 2 = 1

So, a + b = 2


Now, we can solve these two equations to get:

a = 1 - √3 and b = 1 + √3


Thus, the standard deviation of X is:

SD(X) = √Var(X) = √3


Now, we can calculate the required probability:


P(X > 0) = P(Z > (0 - 1) / √3) where Z is the standard normal random variable

= P(Z > -√3 / 3)

= P(Z < √3 / 3)

= 0.63 (from standard normal distribution table)


Conclusion

The probability that the continuous random variable X is greater than 0 is 0.63.
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The continuous random variable X is uniformly distributed with mean1 and variance 3, find P(X 0)?
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