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Price of each article of type P, Q, and R is Rs. 300, Rs. 180 and Rs. 120 respectively. Suresh buys articles of each type in the ratio 3:2:3 in Rs. 6480. How many articles of type Q did he purchase?
- a)14
- b)20
- c)8
- d)None of the above
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
Price of each article of type P, Q, and R is Rs. 300, Rs. 180 and Rs. ...
Let the common factor be k.
Hence, the number of articles of type P, Q and R will be 3k, 2k and 3k respectively
Also,
Unit price of article x Number of articles = Total amount for the articles
∴ 300 x 3k + 180 x 2k + 120 x 3k = 6480
∴ k = 4
∴ Number of articles of Type Q = 2k = 8
Hence, the number of articles of type P, Q and R will be 3k, 2k and 3k respectively
Also,
Unit price of article x Number of articles = Total amount for the articles
∴ 300 x 3k + 180 x 2k + 120 x 3k = 6480
∴ k = 4
∴ Number of articles of Type Q = 2k = 8
Most Upvoted Answer
Price of each article of type P, Q, and R is Rs. 300, Rs. 180 and Rs. ...
► Let the common factor be k.
► Hence, the number of articles of type P, Q and R will be 3k, 2k and 3k respectively
► Also, Unit price of article x Number of articles = Total amount for the articles
∴ 300 x 3k + 180 x 2k + 120 x 3k = 6480
⇒ k = 4
∴ Number of articles of Type Q = 2k = 8
► Hence, the number of articles of type P, Q and R will be 3k, 2k and 3k respectively
► Also, Unit price of article x Number of articles = Total amount for the articles
∴ 300 x 3k + 180 x 2k + 120 x 3k = 6480
⇒ k = 4
∴ Number of articles of Type Q = 2k = 8
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Community Answer
Price of each article of type P, Q, and R is Rs. 300, Rs. 180 and Rs. ...
Given:
Price of article P = Rs. 300
Price of article Q = Rs. 180
Price of article R = Rs. 120
Total amount spent by Suresh = Rs. 6480
Ratio of articles purchased = 3:2:3
To find:
Number of articles of type Q purchased by Suresh
Solution:
Let the common ratio be 3x. Then, the number of articles purchased of each type will be:
P = 3x * 3 = 9x
Q = 3x * 2 = 6x
R = 3x * 3 = 9x
Total amount spent by Suresh = (price of P * number of P) + (price of Q * number of Q) + (price of R * number of R)
6480 = (300 * 9x) + (180 * 6x) + (120 * 9x)
6480 = 2700x + 1080x + 1080x
6480 = 4860x
x = 6480/4860
x = 4/3
Number of articles of type Q purchased by Suresh = 6x = 6 * (4/3) = 8
Therefore, Suresh purchased 8 articles of type Q.
Answer: Option C. 8.
Price of article P = Rs. 300
Price of article Q = Rs. 180
Price of article R = Rs. 120
Total amount spent by Suresh = Rs. 6480
Ratio of articles purchased = 3:2:3
To find:
Number of articles of type Q purchased by Suresh
Solution:
Let the common ratio be 3x. Then, the number of articles purchased of each type will be:
P = 3x * 3 = 9x
Q = 3x * 2 = 6x
R = 3x * 3 = 9x
Total amount spent by Suresh = (price of P * number of P) + (price of Q * number of Q) + (price of R * number of R)
6480 = (300 * 9x) + (180 * 6x) + (120 * 9x)
6480 = 2700x + 1080x + 1080x
6480 = 4860x
x = 6480/4860
x = 4/3
Number of articles of type Q purchased by Suresh = 6x = 6 * (4/3) = 8
Therefore, Suresh purchased 8 articles of type Q.
Answer: Option C. 8.
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Price of each article of type P, Q, and R is Rs. 300, Rs. 180 and Rs. 120 respectively. Suresh buys articles of each type in the ratio 3:2:3 in Rs. 6480. How many articles of type Q did he purchase?a)14b)20c)8d)None of the aboveCorrect answer is option 'C'. Can you explain this answer?
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