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In a photoelectric experiment, photons of energy 4.8eV are incident on a metal surface. They liberate
electrons which are just 'stopped' by an electrode at a potential of -3.3 volt with respect to the metal. The work function of the metal surface in electron volt is
electrons which are just 'stopped' by an electrode at a potential of -3.3 volt with respect to the metal. The work function of the metal surface in electron volt is
- a)3.3 eV
- b)8.1 eV
- c)1.5 eV
- d)8 eV
Correct answer is option 'C'. Can you explain this answer?
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In a photoelectric experiment, photons of energy 4.8eV are incident on...
Calculation of the work function of the metal surface
Given:
- Energy of incident photons = 4.8 eV
- Stopping potential = -3.3 V
We know that the stopping potential (V) is related to the maximum kinetic energy (Kmax) of the emitted electrons as follows:
Kmax = eV
where e is the charge of an electron.
Therefore, in this case, we have:
Kmax = -1.6 x 10^-19 C x (-3.3 V) = 5.28 x 10^-19 J
We also know that the energy of a photon (E) is related to the work function (Φ) and the maximum kinetic energy (Kmax) of the emitted electron as follows:
E = Φ + Kmax
Therefore, in this case, we have:
4.8 eV = Φ + 5.28 x 10^-19 J
Converting electron volts (eV) to joules (J):
1 eV = 1.6 x 10^-19 J
Therefore,
4.8 eV = 4.8 x 1.6 x 10^-19 J = 7.68 x 10^-19 J
Substituting this value in the equation above, we get:
7.68 x 10^-19 J = Φ + 5.28 x 10^-19 J
Solving for Φ, we get:
Φ = 7.68 x 10^-19 J - 5.28 x 10^-19 J = 2.4 x 10^-19 J
Converting this value to electron volts (eV):
Φ = 2.4 x 10^-19 J / 1.6 x 10^-19 J/eV = 1.5 eV
Therefore, the work function of the metal surface is 1.5 eV.
Given:
- Energy of incident photons = 4.8 eV
- Stopping potential = -3.3 V
We know that the stopping potential (V) is related to the maximum kinetic energy (Kmax) of the emitted electrons as follows:
Kmax = eV
where e is the charge of an electron.
Therefore, in this case, we have:
Kmax = -1.6 x 10^-19 C x (-3.3 V) = 5.28 x 10^-19 J
We also know that the energy of a photon (E) is related to the work function (Φ) and the maximum kinetic energy (Kmax) of the emitted electron as follows:
E = Φ + Kmax
Therefore, in this case, we have:
4.8 eV = Φ + 5.28 x 10^-19 J
Converting electron volts (eV) to joules (J):
1 eV = 1.6 x 10^-19 J
Therefore,
4.8 eV = 4.8 x 1.6 x 10^-19 J = 7.68 x 10^-19 J
Substituting this value in the equation above, we get:
7.68 x 10^-19 J = Φ + 5.28 x 10^-19 J
Solving for Φ, we get:
Φ = 7.68 x 10^-19 J - 5.28 x 10^-19 J = 2.4 x 10^-19 J
Converting this value to electron volts (eV):
Φ = 2.4 x 10^-19 J / 1.6 x 10^-19 J/eV = 1.5 eV
Therefore, the work function of the metal surface is 1.5 eV.
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In a photoelectric experiment, photons of energy 4.8eV are incident on a metal surface. They liberateelectrons which are just 'stopped' by an electrode at a potential of -3.3 volt with respect to the metal. The work function of the metal surface in electron volt isa)3.3 eV b)8.1 eVc) 1.5 eVd)8 eVCorrect answer is option 'C'. Can you explain this answer?
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In a photoelectric experiment, photons of energy 4.8eV are incident on a metal surface. They liberateelectrons which are just 'stopped' by an electrode at a potential of -3.3 volt with respect to the metal. The work function of the metal surface in electron volt isa)3.3 eV b)8.1 eVc) 1.5 eVd)8 eVCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In a photoelectric experiment, photons of energy 4.8eV are incident on a metal surface. They liberateelectrons which are just 'stopped' by an electrode at a potential of -3.3 volt with respect to the metal. The work function of the metal surface in electron volt isa)3.3 eV b)8.1 eVc) 1.5 eVd)8 eVCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a photoelectric experiment, photons of energy 4.8eV are incident on a metal surface. They liberateelectrons which are just 'stopped' by an electrode at a potential of -3.3 volt with respect to the metal. The work function of the metal surface in electron volt isa)3.3 eV b)8.1 eVc) 1.5 eVd)8 eVCorrect answer is option 'C'. Can you explain this answer?.
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