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For the reaction,2no O2=2No,the volume is suddenly reduced to half of its value by increasing pressure on it ,if reaction is of first order w.r.t.o2 and second order w.r.t .NO,the rate of the reaction will?
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For the reaction,2no O2=2No,the volume is suddenly reduced to half of ...


Effect of Volume Reduction on Rate of Reaction

Increasing the pressure on a reaction by reducing the volume can have a significant impact on the rate of the reaction. In this case, the reaction 2NO + O2 → 2NO is considered.

Order of Reaction

The reaction is first order with respect to O2 and second order with respect to NO. This means that the rate of the reaction is directly proportional to the concentration of O2 raised to the power of 1 and the concentration of NO raised to the power of 2.

Effect of Volume Reduction

When the volume is suddenly reduced to half of its value, the concentrations of both O2 and NO will increase due to the reduced volume. According to the rate equation for the reaction, the rate will increase by a factor of 2^1 x 2^2 = 2 x 4 = 8.

Rate of the Reaction

Therefore, the rate of the reaction will increase by a factor of 8 when the volume is reduced to half of its value by increasing pressure on it. This increase in rate is due to the increase in concentrations of the reactants O2 and NO as a result of the volume reduction.
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For the reaction,2no O2=2No,the volume is suddenly reduced to half of ...
Sure, I can help you with that.

The reaction 2NO + O2 → 2NO2 is of first order with respect to O2 and second order with respect to NO. This means that the rate of the reaction is proportional to the concentration of O2 and the square of the concentration of NO.

If the volume of the system is suddenly reduced to half of its value, the concentration of both O2 and NO will be doubled. However, the concentration of NO will be squared, so the overall concentration of NO will increase by a factor of 4.

Therefore, the rate of the reaction will increase by a factor of 8.

Here is the calculation:

Let the initial concentration of O2 be [O2] and the initial concentration of NO be [NO]. The initial rate of the reaction is given by

R = k[O2][NO]^2
where k is the rate constant.

After the volume of the system is reduced to half of its value, the concentration of O2 and NO will be doubled, so the new rate of the reaction is given by

R' = k[2O2][2NO]^2 = 8k[O2][NO]^2 = 8R
Therefore, the rate of the reaction will increase by a factor of 8.

As you can see, the answer is option d.
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For the reaction,2no O2=2No,the volume is suddenly reduced to half of its value by increasing pressure on it ,if reaction is of first order w.r.t.o2 and second order w.r.t .NO,the rate of the reaction will?
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For the reaction,2no O2=2No,the volume is suddenly reduced to half of its value by increasing pressure on it ,if reaction is of first order w.r.t.o2 and second order w.r.t .NO,the rate of the reaction will? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about For the reaction,2no O2=2No,the volume is suddenly reduced to half of its value by increasing pressure on it ,if reaction is of first order w.r.t.o2 and second order w.r.t .NO,the rate of the reaction will? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For the reaction,2no O2=2No,the volume is suddenly reduced to half of its value by increasing pressure on it ,if reaction is of first order w.r.t.o2 and second order w.r.t .NO,the rate of the reaction will?.
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