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If on March 10, 1823 it was Monday, then what was the day of the week on March 10, 1825?
  • a)
    Tuesday
  • b)
    Wednesday
  • c)
    Thursday
  • d)
    Friday
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
If on March 10, 1823 it was Monday, then what was the day of the week ...
In an ordinary year, there are 365 days and on dividing 365 by 7 we get remainder = 1 so this extra one day is taken as an odd day.
Similarly, in a leap year, there are 366 days and on dividing 366 by 7 we get remainder = 2 so these extra 2 days are taken as the odd days.
Thus, the remainder which we get after dividing a number of days by 7 is considered as odd days.
Now, we have to calculate the odd days from March 10, 1823 – March 09, 1825.
March 10, 1823 – March 09, 1824 = 366 days = 2 odd days (as 1824 is the leap year and 29th Feb is included in this period)
March 10, 1824 – March 09, 1825 = 365 day = 1 odd day
Total odd days = 3
Thus, March 10, 1823 is 3 days (of the week) beyond the day of March 10, 1825.
March 10, 1823 (Monday) → March 10, 1825 (Thursday)
Hence, Thursday is the correct answer.
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Most Upvoted Answer
If on March 10, 1823 it was Monday, then what was the day of the week ...
In an ordinary year, there are 365 days and on dividing 365 by 7 we get remainder = 1 so this extra one day is taken as an odd day.
Similarly, in a leap year, there are 366 days and on dividing 366 by 7 we get remainder = 2 so these extra 2 days are taken as the odd days.
Thus, the remainder which we get after dividing a number of days by 7 is considered as odd days.
Now, we have to calculate the odd days from March 10, 1823 – March 09, 1825.
March 10, 1823 – March 09, 1824 = 366 days = 2 odd days (as 1824 is the leap year and 29th Feb is included in this period)
March 10, 1824 – March 09, 1825 = 365 day = 1 odd day
Total odd days = 3
Thus, March 10, 1823 is 3 days (of the week) beyond the day of March 10, 1825.
March 10, 1823 (Monday) → March 10, 1825 (Thursday)
Hence, Thursday is the correct answer.
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Community Answer
If on March 10, 1823 it was Monday, then what was the day of the week ...
Calculation:
To determine the day of the week on March 10, 1825, we need to understand the pattern of days in a year and account for the leap year.

Leap Year:
1824 was a leap year because it is divisible by 4. February in a leap year has 29 days.

Days in 1823:
From March 10, 1823, to March 10, 1824, there are 366 days in total (including the extra day in February).

Days in 1824:
From March 10, 1824, to March 10, 1825, there are 365 days.

Calculating the Day:
Since 1824 was a leap year, the day of the week moved one day ahead. So, if March 10, 1823, was Monday, March 10, 1825, would be one day ahead of Monday, which is Tuesday.
Therefore, the day of the week on March 10, 1825, was Tuesday.
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If on March 10, 1823 it was Monday, then what was the day of the week on March 10, 1825?a)Tuesdayb)Wednesdayc)Thursdayd)FridayCorrect answer is option 'C'. Can you explain this answer?
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