Point charge q1=2uC and q2= -1uC are kept at points x=0 and x=6 respec...
The electrical potential at a point due to a point charge q is given by the formula:
V = kq/r
where k is the Coulomb constant (k=8.99x10^9 Nm^2/C^2), q is the point charge, and r is the distance between the point charge and the point at which potential is to be calculated.
For point 1, the distance from q1 to point 1 is 2 units and the distance from q2 to point 1 is 4 units. Therefore, the potential due to q1 at point 1 is:
V1 = kq1/2
and the potential due to q2 at point 1 is:
V2 = kq2/4
The total potential at point 1 is the sum of the potentials due to q1 and q2:
V1+V2 = kq1/2 + kq2/4
Substituting the given values q1=2uC and q2=-1uC, we get:
V1+V2 = (8.99x10^9)(2x10^-6)/2 - (8.99x10^9)(1x10^-6)/4
V1+V2 = 4.495 - 2.2475
V1+V2 = 2.2475 V
Since both q1 and q2 have opposite charges, the potential at some point between them will be zero. Therefore, the potential at point 1 will not be zero.
Point charge q1=2uC and q2= -1uC are kept at points x=0 and x=6 respec...
x=4 nd x=12. see, potential depends on magnitude only..chck all options from start.. don't chck both value of x bcs if one fulfills,other will also.( V=kq/r). so at any point, potential due to both charges will be kq1/r1 +kq2/r2. in this case, k 2/r1 -- k 1/r2, tht is for zero potential, 2/r1 -- 1/ r2 =0. at x= 4, r1= 4 nd r2 = 6--4 =2, V= 2/4--1/2 =0. verify for x=12,it will automatically come true. at x=12, r1= 12 nd r2= 12--6 =6, V= 2/12 -- 1/6 =0.
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