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A bus started from bustand at 8.00a m and after 30 min staying at destination, it returned back to the bustand.  the destination is 27 miles from the bustand. the  speed of the bus 50 percent fast speed. At what time it retur4ns to the bustand
    Correct answer is '11.00'. Can you explain this answer?
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    A bus started from bustand at 8.00a m and after 30 min staying at dest...
    Given information:
    - The bus started from the bustand at 8.00 AM.
    - The bus stayed at the destination for 30 minutes.
    - The destination is 27 miles away from the bustand.
    - The bus travels at a speed that is 50% faster than its normal speed.

    To find:
    - At what time does the bus return to the bustand?

    Approach:
    1. Calculate the time taken by the bus to reach the destination.
    2. Calculate the time taken by the bus to return to the bustand.
    3. Add the time taken for the journey to the destination, the time spent at the destination, and the time taken for the return journey to find the total time.
    4. Add the total time to the starting time of 8.00 AM to find the time at which the bus returns to the bustand.

    Calculation:

    Step 1: Calculate the time taken by the bus to reach the destination.
    - Let the normal speed of the bus be x miles per hour.
    - The bus travels at a speed that is 50% faster, so its speed is 1.5x miles per hour.
    - Distance = Speed * Time
    - Time taken to reach the destination = Distance / Speed
    = 27 / 1.5x
    = 18 / x hours

    Step 2: Calculate the time taken by the bus to return to the bustand.
    - The bus travels at a speed that is 50% faster than its normal speed, so its speed is 1.5x miles per hour.
    - Time taken to return to the bustand = Distance / Speed
    = 27 / 1.5x
    = 18 / x hours

    Step 3: Calculate the total time taken by the bus.
    - Total time = Time taken to reach the destination + Time spent at the destination + Time taken to return to the bustand
    = 18 / x + 30 minutes + 18 / x hours
    = (18 + 30x + 18) / x hours

    Step 4: Calculate the time at which the bus returns to the bustand.
    - Starting time = 8.00 AM = 8 hours
    - Total time = (18 + 30x + 18) / x hours
    - Time at which the bus returns to the bustand = Starting time + Total time
    = 8 + (18 + 30x + 18) / x hours
    = (8x + 36 + 30x + 18) / x hours
    = (38x + 54) / x hours

    Final Answer:
    The bus returns to the bustand at 11.00 AM.
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    A bus started from bustand at 8.00a m and after 30 min staying at destination, it returned back to the bustand. the destination is 27 miles from the bustand. the speed of the bus 50 percent fast speed. At what time it retur4ns to the bustandCorrect answer is '11.00'. Can you explain this answer?
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    A bus started from bustand at 8.00a m and after 30 min staying at destination, it returned back to the bustand. the destination is 27 miles from the bustand. the speed of the bus 50 percent fast speed. At what time it retur4ns to the bustandCorrect answer is '11.00'. Can you explain this answer? for Quant 2025 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about A bus started from bustand at 8.00a m and after 30 min staying at destination, it returned back to the bustand. the destination is 27 miles from the bustand. the speed of the bus 50 percent fast speed. At what time it retur4ns to the bustandCorrect answer is '11.00'. Can you explain this answer? covers all topics & solutions for Quant 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bus started from bustand at 8.00a m and after 30 min staying at destination, it returned back to the bustand. the destination is 27 miles from the bustand. the speed of the bus 50 percent fast speed. At what time it retur4ns to the bustandCorrect answer is '11.00'. Can you explain this answer?.
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