NEET Exam  >  NEET Questions  >  Two equal charges are placed at a separation ... Start Learning for Free
Two equal charges are placed at a separation of 1.0m. What should be the magnitude of the charges so that the force between them equals the weight of a 50 kg person?
Verified Answer
Two equal charges are placed at a separation of 1.0m. What should be t...
Charges `q` each, AB = 1 m
wt, of 50kg person
= 50 x g = 50 x 9.8 = 490N
The electrostatic force is given as:
FC ​= kqq2/r2 
∴ kq2 / r2 = 490N
⇒ q2 = 490 x r^2 / 9 x 10^9 ​= 490 x 1 x 1 / 9 x 10^9
⇒ q = √54.5 x 10 −9 ​= 23.323 x 10^−5 C ≈ 2.3 x 10^−4 coulomb.
This question is part of UPSC exam. View all NEET courses
Most Upvoted Answer
Two equal charges are placed at a separation of 1.0m. What should be t...
Calculation of charge required to equalize the force

To calculate the charge required to equalize the force, we need to use Coulomb's law formula:

F = k q1 q2 / r^2

where F is the force, k is Coulomb's constant, q1 and q2 are the charges, and r is the separation distance.

We can set the force equal to the weight of a 50 kg person, which is:

F = m g = (50 kg) (9.81 m/s^2) = 490.5 N

We can also set the separation distance to 1.0 m.

Plugging in these values into Coulomb's law, we get:

490.5 N = k q^2 / (1.0 m)^2

Solving for q, we get:

q = sqrt(490.5 N * (1.0 m)^2 / k) = 1.69 x 10^-6 C

Therefore, the magnitude of the charges should be 1.69 x 10^-6 C.

Explanation of the solution

The force between two charges is given by Coulomb's law, which states that the force is proportional to the product of the charges and inversely proportional to the square of the separation distance. Therefore, if we want to equalize the force between two charges to the weight of a 50 kg person, we can set the force equal to the weight and solve for the charge.

Coulomb's constant, k, is a physical constant that relates the electrostatic force between two charges to the product of the charges and the separation distance. Its value is approximately 9 x 10^9 N m^2 / C^2.

The charge required to equalize the force is very small, which is expected because the electrostatic force is much stronger than the gravitational force between two small charges.
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
Explore Courses for NEET exam

Top Courses for NEET

Two equal charges are placed at a separation of 1.0m. What should be the magnitude of the charges so that the force between them equals the weight of a 50 kg person?
Question Description
Two equal charges are placed at a separation of 1.0m. What should be the magnitude of the charges so that the force between them equals the weight of a 50 kg person? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two equal charges are placed at a separation of 1.0m. What should be the magnitude of the charges so that the force between them equals the weight of a 50 kg person? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two equal charges are placed at a separation of 1.0m. What should be the magnitude of the charges so that the force between them equals the weight of a 50 kg person?.
Solutions for Two equal charges are placed at a separation of 1.0m. What should be the magnitude of the charges so that the force between them equals the weight of a 50 kg person? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of Two equal charges are placed at a separation of 1.0m. What should be the magnitude of the charges so that the force between them equals the weight of a 50 kg person? defined & explained in the simplest way possible. Besides giving the explanation of Two equal charges are placed at a separation of 1.0m. What should be the magnitude of the charges so that the force between them equals the weight of a 50 kg person?, a detailed solution for Two equal charges are placed at a separation of 1.0m. What should be the magnitude of the charges so that the force between them equals the weight of a 50 kg person? has been provided alongside types of Two equal charges are placed at a separation of 1.0m. What should be the magnitude of the charges so that the force between them equals the weight of a 50 kg person? theory, EduRev gives you an ample number of questions to practice Two equal charges are placed at a separation of 1.0m. What should be the magnitude of the charges so that the force between them equals the weight of a 50 kg person? tests, examples and also practice NEET tests.
Explore Courses for NEET exam

Top Courses for NEET

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev