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The addition of HBr to alkenes in the presence of peroxides is called :
- a)free radical addition reaction
- b)carbocation addition reaction
- c)nucleophilic addition reaction
- d)electrophilic addition reaction
Correct answer is option 'A'. Can you explain this answer?
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The addition of HBr to alkenes in the presence of peroxides is called ...
Addition reaction of HBr to an alkene in the presence of peroxide follows the free-radical mechanism. Here, bromine radical is formed which reacts with an alkene and produces an anti-markovnikov product. So, the correct answer is option 'A'.
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The addition of HBr to alkenes in the presence of peroxides is called ...
Free Radical Addition Reaction
The addition of HBr to alkenes in the presence of peroxides is a type of free radical addition reaction. This reaction involves the formation of free radicals, which are highly reactive species with unpaired electrons.
Mechanism of Free Radical Addition Reaction
The mechanism of free radical addition reaction can be divided into three main steps:
1. Initiation: In the presence of peroxides, the HBr molecule is broken down into two free radicals: H● and Br●. This is known as the initiation step, and it occurs due to the homolytic cleavage of the peroxide bond.
2. Propagation: The H● free radical reacts with the alkene, forming a new free radical at the site of the double bond. This new free radical reacts with a molecule of HBr, forming a new product and regenerating the original free radical. This process is known as the propagation step, and it continues until all the alkene molecules have been consumed.
3. Termination: The final step in the free radical addition reaction is the termination step, in which two free radicals combine to form a stable molecule. This can occur in a number of ways, including the combination of two H● free radicals to form H2, or the combination of an H● and a Br● free radical to form HBr.
Conclusion
In conclusion, the addition of HBr to alkenes in the presence of peroxides is a type of free radical addition reaction. The reaction mechanism involves the formation of free radicals, which are highly reactive species with unpaired electrons. The reaction proceeds through three main steps: initiation, propagation, and termination.
The addition of HBr to alkenes in the presence of peroxides is a type of free radical addition reaction. This reaction involves the formation of free radicals, which are highly reactive species with unpaired electrons.
Mechanism of Free Radical Addition Reaction
The mechanism of free radical addition reaction can be divided into three main steps:
1. Initiation: In the presence of peroxides, the HBr molecule is broken down into two free radicals: H● and Br●. This is known as the initiation step, and it occurs due to the homolytic cleavage of the peroxide bond.
2. Propagation: The H● free radical reacts with the alkene, forming a new free radical at the site of the double bond. This new free radical reacts with a molecule of HBr, forming a new product and regenerating the original free radical. This process is known as the propagation step, and it continues until all the alkene molecules have been consumed.
3. Termination: The final step in the free radical addition reaction is the termination step, in which two free radicals combine to form a stable molecule. This can occur in a number of ways, including the combination of two H● free radicals to form H2, or the combination of an H● and a Br● free radical to form HBr.
Conclusion
In conclusion, the addition of HBr to alkenes in the presence of peroxides is a type of free radical addition reaction. The reaction mechanism involves the formation of free radicals, which are highly reactive species with unpaired electrons. The reaction proceeds through three main steps: initiation, propagation, and termination.
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The addition of HBr to alkenes in the presence of peroxides is called :a) free radical addition reaction b) carbocation addition reaction c) nucleophilic addition reaction d) electrophilic addition reaction Correct answer is option 'A'. Can you explain this answer?
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