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An eight-pole wound rotor induction motor operation on 60 Hz supply is driven at 1800 rpm by a prime mover in the opposite direction of the revolving magnetic field. The frequency of rotor current is-
  • a)
    4800 Hz
  • b)
    180 Hz
  • c)
    400 Hz
  • d)
    200 Hz
Correct answer is option 'B'. Can you explain this answer?
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An eight-pole wound rotor induction motor operation on 60 Hz supply is...
Prime mover in the opposite direction of revolving magnetic field
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An eight-pole wound rotor induction motor operation on 60 Hz supply is...
Prime mover in the opposite direction of revolving magnetic field
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An eight-pole wound rotor induction motor operation on 60 Hz supply is...
Frequency of Rotor Current in a Wound Rotor Induction Motor

Given:
- Eight-pole wound rotor induction motor
- Operates on 60 Hz supply
- Driven at 1800 rpm by a prime mover in the opposite direction of the revolving magnetic field

To find: Frequency of rotor current

Solution:
1. Synchronous speed (Ns) of the motor:
- Ns = (120 * f) / P
- Where f = frequency of the supply and P = number of poles
- Ns = (120 * 60) / 8 = 900 rpm

2. Slip (s) of the motor:
- s = (Ns - N) / Ns
- Where N = speed of the motor
- s = (900 - 1800) / 900 = -1

3. Frequency of rotor current (fr):
- fr = s * f
- fr = -1 * 60 = -60 Hz

4. Since the frequency of current cannot be negative, we take the absolute value of fr:
- fr = 60 Hz

5. However, the rotor current frequency is relative to the stator frequency, so we need to calculate the difference between the two:
- Difference = |f - fr|
- Difference = |60 - 60| = 0 Hz

6. Therefore, the frequency of rotor current is 60 Hz, which is the same as the supply frequency.

Answer: Option (B) 180 Hz
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An eight-pole wound rotor induction motor operation on 60 Hz supply is driven at 1800 rpm by a prime mover in the opposite direction of the revolving magnetic field. The frequency of rotor current is-a)4800 Hzb)180 Hzc)400 Hzd)200 HzCorrect answer is option 'B'. Can you explain this answer?
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