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If in an R-L-C series circuit, the frequency is below the resonant frequency, then-
- a)Xc < XL
- b)Xc > XL
- c)Xc = XL
- d)None of the above
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
If in an R-L-C series circuit, the frequency is below the resonant fre...
In series resonance circuit, below resonance frequency is capacitive nature Xc > XL and above resonance frequency is inductive nature Xc = XL .
Most Upvoted Answer
If in an R-L-C series circuit, the frequency is below the resonant fre...
Is greater than Xl
b)Xl is greater than Xc
c)Impedance is minimum
d)Impedance is maximum
Answer: b) Xl is greater than Xc.
Explanation:
In an R-L-C series circuit, the impedance Z is given by:
Z = R + j(Xl - Xc)
where R is the resistance, Xl is the inductive reactance, and Xc is the capacitive reactance.
At resonance (when the frequency is equal to the resonant frequency), Xl = Xc, and the impedance Z is minimum.
When the frequency is below the resonant frequency, Xc > Xl, and the impedance Z is dominated by the capacitive reactance. Therefore, the impedance Z is higher than at resonance, and option d) is incorrect.
Since Xc > Xl, the total reactance (Xl - Xc) is negative, which means that the circuit behaves as a predominantly inductive circuit. Therefore, option a) is incorrect.
Option c) is also incorrect because the impedance Z is not minimum when the frequency is below resonance.
Therefore, the correct answer is b) Xl is greater than Xc.
b)Xl is greater than Xc
c)Impedance is minimum
d)Impedance is maximum
Answer: b) Xl is greater than Xc.
Explanation:
In an R-L-C series circuit, the impedance Z is given by:
Z = R + j(Xl - Xc)
where R is the resistance, Xl is the inductive reactance, and Xc is the capacitive reactance.
At resonance (when the frequency is equal to the resonant frequency), Xl = Xc, and the impedance Z is minimum.
When the frequency is below the resonant frequency, Xc > Xl, and the impedance Z is dominated by the capacitive reactance. Therefore, the impedance Z is higher than at resonance, and option d) is incorrect.
Since Xc > Xl, the total reactance (Xl - Xc) is negative, which means that the circuit behaves as a predominantly inductive circuit. Therefore, option a) is incorrect.
Option c) is also incorrect because the impedance Z is not minimum when the frequency is below resonance.
Therefore, the correct answer is b) Xl is greater than Xc.
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If in an R-L-C series circuit, the frequency is below the resonant frequency, then-a)Xc< XLb)Xc >XLc)Xc =XLd)None of the aboveCorrect answer is option 'C'. Can you explain this answer?
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